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12 days ago

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Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month

for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. How many months will it take for the second phone to be less expensive than the first phone?
The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is 100 + 55x > 150 + 51x100 + 55x < 150 + 51x100x+ 55 > 150x+ 51100x+ 55 < 150x+ 51.

The solution to the inequality is x > 2.4x < 2.4x < 12.5x > 12.5.

Sal’s mother would have to keep the second cell phone plan for at least 231213 months in order for it to be less expensive

2 answers:

Leona [4.1K]12 days ago

8 0

Answer:

Part 1:

The initial phone has a cost of $100 and a monthly charge of $55 for unlimited usage.

Let f(x) denote the cost of the first phone, with x representing the months.

Equation forms:

$f(x)=55x+100$

The second phone costs $150, with a monthly rate of $51 for unlimited service.

Let g(x) denote the cost of the second phone, with x as the number of months.

Equation forms:

$g(x)=51x+150$

We need to establish the inequality that shows the months, x, required for the second phone's cost to be lesser. This is given by:

$g(x)$

$51x+150$

Part 2:

The inequality solution is:

$51x+150$

=> $51x-55x$

=> $-4x$

=> $-x$

=> $x>12.5$

Or rounded to 13 months.

Part 3:

For the second phone plan to be less costly, Sal's mother needs to keep it for no less than 13 months.

AnnZ [3.9K]12 days ago

8 0

Answer:

a) The first inequality is 100 + 55x > 150 + 51x;

b) The final inequality results in x > 12.5

c) Sal's mother will need to use the second phone for at least 13 months.

Step-by-step explanation:

a) Let x represent the number of months.

1. The first phone is priced at $100, with a monthly fee of $55 for unlimited use, leading to a total cost of $(100 + 55x) for x months.

2. The second phone costs $150 with a monthly fee of $51 for unlimited use, resulting in a total of $(150 + 51x) for x months.

3. For the second phone to be cheaper, we set up the inequality:

150 + 51x < 100 + 55x

which simplifies to

100 + 55x > 150 + 51x

b) Now solve this:

55x - 51x > 150 - 100

4x > 50

so x > 12.5

c) This means Sal's mother has to retain the second phone for at least 13 months (since x > 12.5).

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