One is the additive identity. True or False

A(w) = -w² + 100w Step-by-step explanation: Initially, we need to express the length (l) of the rectangular area in terms of the width (w). Given that the total perimeter of the rectangle is 200 feet implies that 2(w + l) = 200, leading to l = 100 - w. Hence, the area A can be given as width multiplied by length: A = w * l = w * (100 - w) = -w² + 100w. Consequently, A(w) = -w² + 100w.

Response:

Each associate incurs a cost of $700 daily for the client, meaning that 'a' associates will cost the client 700a dollars each day. For each partner, the charge is $1500 daily, so 'p' partners will accumulate a cost of 1500p dollars daily. The cumulative bill amounts to 700a + 1500p = $14100:

700a + 1500p = 14100

700a + 1500p = 14100

Given that there are a total of 11 lawyers assigned (associates and partners), the equation a + p must equal 11.

a + p = 11

a + p = 11

\underline{\text{Formulate System of Equations:}}

Formulate System of Equations:

​

700a + 1500p =

700a + 1500p = 14100

14100

a + p = 11

11

Answer:

(a)

The distance from A to B to C equals 40 yards.

(b)

w is less than 40.

Step-by-step explanation:

The information provided states:

The distance from A to B is 15 yards.

Thus, AB is 15 yards.

The distance from B to C is 25 yards.

Therefore, BC is 25 yards.

(a)

The total distance from A to B to C is given by AB plus BC.

A to B to C = 15 + 25.

The total distance is 40 yards.

(b)

The direct distance from A to C (AC) must be shorter than the length of A to B to C.

AC is less than AB plus BC.

AC must be less than 15 + 25.

Thus, AC is less than 40 yards.

w is less than 40.

C 35.64 I have previous experience with this.

A normal distribution is most effective when dealing with a substantial sample size. Without knowing how many containers there are, it's challenging to determine if it’s suitable for modeling the container weights.