The correct answer is "His teacher advised it because he did not have time to tutor Euler privately." I completed the assignment and got it correct.
The weight of an orangutan is 64.5 kilograms
Solution:
It is stated that the orangutan's weight is 142 pounds
Additionally,
1 kilogram is approximately 2.2 pounds
We will now convert 142 pounds into kilograms
1 kilogram = 2.2 pounds

As a result, 142 pounds translates to


When rounding to the nearest tenth, we obtain 64.5 kilograms
Therefore the mass of the orangutan is 64.5 kilograms
Response:
MAD value comes out to be 3.
Detailed Breakdown:
The given sales forecasts for the last four months are 5, 6, 11, and 12 units.
To calculate the Mean Absolute Deviation (MAD) for these forecasts:
The average of the forecasts across four months is
.
Thus, the total of absolute differences between the forecast values and the average is = |5 - 8.5| + |6 - 8.5| + |11 - 8.5| + |12 - 8.5| = 3.5 + 2.5 + 2.5 + 3.5 = 12.
Hence, the MAD value will be =
(Final Answer)
To formulate the system, it's necessary to consider the slope of each line along with at least one point from each line. The two lines will connect each plane's location to their destination airport. It's important to note that the airport's coordinates represent the intersection of these two lines, corresponding to the solution of the system. First, the slope of the line from airplane one to the airport is: m = 2; this can be observed by plotting the two points. From airplane 1's location, the rise is 8 units while the run is 4 units to reach the airport, making the slope 8 divided by 4 = 2. We then insert the slope and point (2,4) into the point-slope form: y - 4 = 2(x - 4), which can be rearranged to standard form 2x - y = 0. For airplane two, the slope to the airport is obtained by observing the vertical decrease of 3 and a horizontal increase of 9 as we move from the airport to airplane 2. We then substitute the slope and the point (15,9) into the point-slope form: y - 9 = -1/3(x - 15), which can be rearranged to the standard form: x + 3y = 42. Consequently, the system of equations is: 2x - y = 0 and x + 3y = 42. Multiplying the first equation by 3 produces a system of: 6x - 3y = 0 and x + 3y = 42. Adding these equations results in the equation 7x = 42. Thus, x = 6, and by substituting this value back into 2x - y = 0, we determine y = 12. Thus, we demonstrate that the airport's coordinates do indeed comprise the solution to our system.
Answer: C. Significant at 0.036
Step-by-step explanation:
Given:
Total samples selected Ns= 500
Airplanes that arrived on time Na = 482.
Airplanes that arrived late Nl = 500 - 482 = 18
Calculating the probability of an airplane arriving late:
P(L) = Nl/Ns
P(L) = 18/500
P(L) = 0.036
An event is deemed significant if its probability is equal to or less than 0.05.
As P(L) < 0.05
P(L) = Significant at 0.036