Answer:
A), B), and C) are clarified below.
Step-by-step explanation:
The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.
Simplifying gives us
P[k] = nCk / 2^n
A. Probability of all bits being 1s
16c16/2^16 = 1/65536
B. Probability of all bits being 0s
16c0/2^16 = 1/65536
C. The probability of having exactly 8 bits as 1s and the other 8 as 0s
16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%