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Anuta_ua
23 days ago
7

A square has a side length of 1.2 feet. If the square is dilated by a factor of 2.5, what is the length of a side of the new squ

are?
Mathematics
1 answer:
tester [12.3K]23 days ago
4 0
It begins at 1.2 feet. In mathematics, dilation implies resizing, thus I will provide both possible results. Confirm with your teacher the expectation of the question. For enlargement, 1.2 * 2.5 equals 3, and for reduction, 1.2 divided by 2.5 equals 0.48.
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How many times greater is the value of the 3 in 4,367 than the value of the 3 in 39?​
Inessa [12570]
Approximately 111.97
8 0
12 days ago
for the level 3 course, examination hours cost twice as much as workshop hours and workshop hours cost twice as much as lecture
Leona [12618]

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.

6 0
1 month ago
Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy
Leona [12618]

Answer:

Hello! Your question appears to be missing details; here is the complete version

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

Step-by-step explanation:

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

This provides a comprehensive solution below

4 0
1 month ago
Mark and robyn used base-ten blocks to show that 200 is 100 times as much as 2. Whose model makes sense whose model is nonsense?
babunello [11817]

Answer:

Robyn's model is logical, while Mark's is illogical.

Step-by-step explanation:

This question doesn't require calculations. What we need to do is analyze each model logically.

Mark's

Mark's representation indicates 20 instead of 2, which signifies that 200 is ten times greater than 20, making it nonsensical.

Robyn's

Robyn's representation displays 2, suggesting that 200 is 100 times greater than 2, which is not only accurate but also reasonable since 100 * 2 equals 200.

4 0
1 month ago
Lesson 3 homework practice mean absolute deviation
AnnZ [12381]
To calculate the mean absolute deviation of
1,2,3,4,5,6,7
, we start by finding the mean;
 (1+2+3+4+5+6+7) =28/7
                               = 4
. Next, we determine the absolute differences of each data point from the mean (x-μ)
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. The absolute values are 3,2,1,0,1,2,3
. Now we compute the mean of these absolute differences,
3+2+1+0+1+2+3 = 12
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                           = 1.7143
. Thus, the mean is 4, and the Mean absolute deviation comes out to be 1.7143
4 0
1 month ago
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