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MakcuM
13 days ago
8

A gas can is filled at the rate of 320 cubic inches per minute. The cab is 10 inches long, 8 inches wide, and 12 inches high. Ho

w many minutes will it take to fill the can?
Mathematics
2 answers:
tester [8.8K]12 days ago
5 0
The dimensions of the can are 10 inches long, 8 inches wide, and 12 inches high. The volume of the cuboid can is calculated as follows: Volume of the can = 960 cubic inches. Given that the gas can is being filled at a rate of 320 cubic inches per minute, we can determine the total time needed to fill the can by dividing its volume by the filling rate: Total minutes to fill the can = Volume of the can divided by the Rate at which gas is filled = 960/320 = 3 minutes. Therefore, it will take 3 minutes to completely fill the can.
Inessa [9K]12 days ago
3 0
3 minutes. 10*8*12=960 cubic inches. Dividing 960 by 320 inches per minute gives 3.
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In the diagram, AB and EF are horizontal lines and CB is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates o
Inessa [9000]
In response to the earlier inquiry, the diagram depicts horizontal lines along with a vertical segment; FB measures 3. If C is defined as 3, then the coordinates for point D would be (-6,-4). I trust this response has clarified your question.
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17 days ago
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Fill in the blanks. a. A​ relative-frequency distribution is to a variable as a​ __________ distribution is to a random variable
AnnZ [9099]

Answer:

a. A relative-frequency distribution relates to a variable just as a _____probability_____ distribution relates to a random variable. b. A relative-frequency histogram pertains to a variable similarly to how a _____probability_____ histogram pertains to a random variable.

Step-by-step explanation:

Probability, a mathematical concept, involves numerical assessments of how likely a certain event may occur, indicating the validity of its occurrence. The range for the probability of any event is typically between 0 and 1,

with 0 signifying impossibility and 1 indicating certainty of occurrence.

4 0
1 month ago
Julia can finish a 20-mile bike ride in 1.2 hours. Katie can finish the same bike ride in 1.6 hours. How much faster does Julia
Svet_ta [9500]

Given that,speed = \frac{distance}{time}

Julia completes a 20-mile bike ride in 1.2 hours.

The distance Julia covers is 20 miles and her time taken is 1.2 hours.

Therefore, Julia's speed = \frac{20}{1.2} = 16.67 mph


Katie finishes the same 20-mile ride in 1.6 hours.

Katie’s distance is 20 miles and her time is 1.6 hours.

Hence, Katie's speed = \frac{20}{1.6} = 12.5 mph


To determine how much faster Julia rides compared to Katie, subtract Katie’s speed from Julia’s speed.

Thus, 16.67 mph minus 12.5 mph equals 4.17 mph, approximately 4.2 mph.

Consequently, Julia cycles 4.2 mph faster than Katie.

5 0
1 month ago
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Finally, suppose m1→∞, while m2 remains finite. what value does the the magnitude of the tension approach?
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The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>
5 0
1 month ago
Sean took the bus from Seattle to Boise, a distance of 506 miles. If the trip took 723 hours, what was the speed of the bus?
AnnZ [9099]

Answer:

0.69 miles per hour

Step-by-step explanation:

speed = distance/time

speed = 506/723

506/723 = 0.69

4 0
15 days ago
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