Answer:
a) 0.00019923%
b) 47.28%
Step-by-step explanation:
a) To determine the likelihood that all sockets in the sample are defective, we can use the following approach:
The first socket is among a group that has 5 defective out of 38, leading to a probability of 5/38.
The second socket is then taken from a group of 4 defective out of 37, following the selection of the first defective socket, resulting in a probability of 4/37.
Extending this logic, the chance of having all 5 defective sockets is computed as: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%.
b) Using similar reasoning as in part a, the first socket has a probability of 33/38 of not being defective as it's chosen from a set where 33 sockets are functionally sound. The next socket has a proportion of 32/37, and this continues onward.
The overall probability calculates to (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%.
To formulate the system, it's necessary to consider the slope of each line along with at least one point from each line. The two lines will connect each plane's location to their destination airport. It's important to note that the airport's coordinates represent the intersection of these two lines, corresponding to the solution of the system. First, the slope of the line from airplane one to the airport is: m = 2; this can be observed by plotting the two points. From airplane 1's location, the rise is 8 units while the run is 4 units to reach the airport, making the slope 8 divided by 4 = 2. We then insert the slope and point (2,4) into the point-slope form: y - 4 = 2(x - 4), which can be rearranged to standard form 2x - y = 0. For airplane two, the slope to the airport is obtained by observing the vertical decrease of 3 and a horizontal increase of 9 as we move from the airport to airplane 2. We then substitute the slope and the point (15,9) into the point-slope form: y - 9 = -1/3(x - 15), which can be rearranged to the standard form: x + 3y = 42. Consequently, the system of equations is: 2x - y = 0 and x + 3y = 42. Multiplying the first equation by 3 produces a system of: 6x - 3y = 0 and x + 3y = 42. Adding these equations results in the equation 7x = 42. Thus, x = 6, and by substituting this value back into 2x - y = 0, we determine y = 12. Thus, we demonstrate that the airport's coordinates do indeed comprise the solution to our system.
To calculate, simply multiply 12 by 0.15 or 15%, which equals 1.8. Then subtract 1.8 from 12, yielding $10.20 as the discounted price for the pizza.
I hope this is helpful
Answer:
Michael purchases 60 kg of dark chocolate alongside 40 kg of milk chocolate.
Step-by-step explanation:
Let d signify the kilograms of dark chocolate bought by Michael and m signify the kilograms of milk chocolate he acquires.
He must acquire a total of 100 kg of chocolate, thus
With dark chocolate priced at $12 per kg, the cost for d kg would be $12d. The price of milk chocolate is $10 per kg, indicating the cost for m kg is $10m. Michael intends to spend $1,120 on the chocolate, therefore
Taking the first equation
By inserting this into the second equation:
Michael ends up buying 60 kg of dark chocolate and 40 kg of milk chocolate.
The x intercept is at (12,0). To find it, start with the equation 1.5x + 4.5y = 18, and subtract 1.5x from both sides. This gives you 4.5y = -1.5x + 18. Next, divide everything by 4.5, resulting in y = -1/3x + 4. Hence, the slope of the line is -1/3, and the y intercept is at (0,4). To determine the x intercept, set y to 0. Plugging this into the equation yields: 1.5x + 4.5(0) = 18, simplifying to 1.5x = 18. Dividing both sides by 1.5 gives x = 12.
