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Kamila
2 months ago
11

Andre wants to make an open-top box by cutting out corners of a 22 inch by 28 inch piece of poster board and then folding up the

sides. The volume  in cubic inches of the open-top box is a function of the side length  in inches of the square cutouts.
Write an expression for .

What is the volume of the box when ?

What is a reasonable domain for  in this context?​
Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
4 0
The formula for the box's volume is V = (length)(width)(height). If we denote the side length of the cutouts as x, we establish V = (28 - 2x)(22 - 2x)(x). Explanation: We intend to excise x by x squares from each corner of a 28 by 22-inch poster board, leading to bottom dimensions of 28 - 2x and 22 - 2x, with a height of x. This expression can be left as is or multiplied and simplified if desired. If we select x = 2 (a random choice as you did not specify), the box's volume calculates to V = (28 - 2*2)(22 - 2*2)(2), rendering V = (24)(18)(2) cubic inches. Since x measures length, it must be greater than zero. Furthermore, the base width of the box can't fall below zero, establishing the inequality for x: 22 - 2x > 0, meaning 11 - x > 0, or x < 11. If we check with x = 10, then V = (28 - 20)(22 - 20)(10). Is this greater than zero? YES. Thus, x < 11 is indeed a reasonable domain in this context.
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tester [12383]

Answer:

The operation r(180°,0) represents a 180° rotation around the origin.

This rotation shifts our shape to the opposite quadrant (effectively translating it across two quadrants).

Thus, this can be seen as:

A reflection across the x-axis followed by a reflection across the y-axis.

Alternatively.

It can also be depicted as a reflection across the y-axis followed by a reflection across the x-axis.

There exists another reflection method, contingent upon the position of our figure.

When the figure is situated in either the first or third quadrant, reflecting over the line y = -x yields a result equivalent to the rotation.

Conversely, if the figure lies in the second or third quadrant, reflecting over the line y = x corresponds to the rotation.

We can merge these two approaches into a single expression:

A reflection over the line y = (-1)^n*x.

Here, n indicates the number identifying the quadrant containing the figure.

8 0
1 month ago
Jenna saves $2,500 per year in an account that earns 10% interest per year, compounded annually. Jenna will have(A $411,234) (B
Leona [12618]

Response:

The result is $43623.50

Detailed explanation:

This query involves compound interest.

The formula for calculating compound interest is

A=P(1+r)^t

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

Provided information

P= $2,500

r= 10/100= 0.1

t= 30 years

Inserting values into the compound interest formula and calculating A gives us

A=2500(1+0.1)^30

A=2500(1.1)^30

A=2500*17.449

A=$43623.50

The total amount is $43623.50

The balance in her account comes from Jenna’s (A annuity payments)

3 0
1 month ago
There are seven boys and five girls in a class. The teacher randomly selects three different students to answer questions. The f
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The likelihood of selecting one girl is calculated as \frac{5}{12}. This is based on having 5 girls within a total of 12 students, and the probability of an event can be expressed as: \frac{\text{# of things you want}}{\text{# of things are possible}}.

Using the same reasoning, for the next student, we have reduced the number of students by 1, leading to 11 possible outcomes instead of 12, giving us:\frac{7}{11}, which represents the probability of selecting a boy as the second choice.

Lastly, the probability of choosing a girl for the third selection follows the same logic and is given as:\frac{4}{10}.

However, we must combine these individual probabilities to determine the likelihood of this specific sequence of selections occurring:

\frac{5}{12}*\frac{7}{11}*\frac{4}{10}=\frac{140}{1320}

This simplifies to:

\frac{7}{66}

4 0
2 months ago
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Lonzell said the function shown in the graph is positive on the interval (−,) and negative on the interval (−,−)open negative 5
Inessa [12570]

Answer:

The segments of the positive graph are located at the coordinates (-5,-4) and (2,5).

In contrast, the negative segment is identified as (-4,2).

Step-by-step explanation:

The positive graph is above the x-axis, while the negative portion lies beneath the y-axis.

Within the interval (-1,5),

The graph appears below the x-axis between (-1,2)

And above it between (2,5).

At this juncture, Lonzell’s assertion is inaccurate.

Within the interval (-5,-1),

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And above it between (-5,4).

At this point, Lonzell's assessment remains incorrect.

Thus,

The segments of the positive graph are at the coordinates (-5,-4) and (2,5).

Meanwhile, the negative segment is identified at (-4,2).

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PIT_PIT [12445]
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