555 grams of wool were needed to knit a sweater, a hat, and a scarf. The hat required 5 times less wool than the sweater and 5 g

Given:

A quadratic function has a line of symmetry positioned at x = –3.5 with one root located at –9.

To find:

The second root.

Solution:

It is understood that the line of symmetry splits the quadratic function's graph into two identical halves. Hence, both roots are equidistant from this line.

This implies that the line of symmetry passes through the midpoint of the two roots.

Let the other root be denoted as x.

Multiply both sides by 2.

Add 9 to both sides.

Consequently, the other zero of the quadratic function is concluded to be 2.

Initial cost = 16000
depreciation rate = 35%
remaining value = 2000
depreciation over one year = 16000*35% = 5600
5600*2 = 11200 + 5600*6\12 = 2000
The car is aged 2.5 years, accounting for two full years and an additional half year of depreciation.

30 candles equal 100%

30% of 100% equals 9 candles from a total of 100 candles

After extinguishing 30% of the candles, 9 will remain lit.

The result I found is 32.761%. Percentage represents any fraction expressed out of 100. It's calculated using the formula: If A is to be expressed as a percentage of B, the formula is A/B * 100. In this case, the paid price for the sweater is $36.20 and the original price is $90.50. We endeavor to find out what percentage reflects the sale price of the sweater. Mathematically, this can be framed as what is 36.20% of 90.5, which translates to (price paid/original price) * 100, and mathematically results in ($36.20/$90.50) * 100 = 32.761. Thus, this indicates that the sweater was sold for 32.761% off its original price.

Answer:

Step-by-step explanation:

a. Create a direction field for the specified differential equation

b. By observing the direction field, comment on the behavior of the solutions as t becomes large.

The solutions seem to oscillate

All solutions appear to approach the function y0(t)=4

All solutions seem to converge to the function y0(t)=0

All solutions appear to have negative slopes eventually and thus decrease indefinitely

All solutions seem to have positive slopes eventually and therefore increase without limit

C

As t approaches infinity

All solutions seem to exhibit positive slopes eventually and thus decrease indefinitely

The solutions seem to gradually approach the function y0(t)=0

All solutions appear to eventually have negative slopes leading to decrease without bounds

All solutions seem to converge to the function y0(t)=4

The results are oscillatory