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20 days ago

5

peggy is putting flowers in vases. she puts either 2 or 3 flowers in each vase. if Peggy has a total of 12 flowers, how many dif

ferent ways can she place them all in the vases?

1 answer:

babunello [11.8K]20 days ago

6 0

2 flores por florero → necesitaría 6 floreros
3 flores por florero → necesitaría 4 floreros
4 flores por florero → necesitaría 3 floreros
6 flores por florero → necesitaría 2 floreros
hay muchas formas de colocar flores en floreros pero esas son algunas.
Espero que haya ayudado.

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Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy

Leona [12618]

Answer:

Hello! Your question appears to be missing details; here is the complete version

Ix = 0 Ux = $\sqrt{y-9z^2}$

Iz = 0 Uz = $\frac{\sqrt{y} }{3}$

Iy = 5 Uy = 10

Step-by-step explanation:

Ix = 0 Ux = $\sqrt{y-9z^2}$

Iz = 0 Uz = $\frac{\sqrt{y} }{3}$

Iy = 5 Uy = 10

This provides a comprehensive solution below

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1 month ago

A neighborhood is trying to set up school carpools, but they need to determine the number of students that need to travel to the

AnnZ [12381]

Answer:

The correct selection is 1.

Step-by-step explanation:

The histogram indicates that

In the 5-10 age group, there are 7 students.

In the 11-13 age group, 5 students are represented.

In the 14-18 age category, 4 students are included.

This implies that the ages of 7 students fall within the 5-10 range, 5 students within the 11-13 range, and 4 students within the 14-18 range.

The total count in the dataset is $7+5+4=16$

In options 3 and 4, the counts in the datasets are fewer than 16. Hence, options 3 and 4 are invalid.

Option 2 exclusively contains data within the 5-10 range, making it incorrect as well.

In option 1,

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11-13 11,11,12,12,13 5

14-18 14,14,15,16 4

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1 month ago

Read 2 more answers

Consider sampling heights from the population of all female college soccer players in the United States. Assume the mean height

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Answer:

B).35

Step-by-step explanation:

The Central Limit Theorem asserts that for a normally distributed variable X, with mean $\mu$ and standard deviation $\sigma$ , sample means' distribution with a size n can be closely approximated by a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

This theorem also applies to skewed variables, provided n is at least 30.

In this scenario:

$\sigma = 3.5, n = 100$

Then

$s = \frac{\sigma}{\sqrt{n}}$

$s = \frac{3.5}{\sqrt{100}}$

$s = 0.35$

Therefore, the right answer is:

B).35

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11 days ago

Identify the equation of the circle that has its center at (-27, 120) and passes through the origin.

zzz [12365]

The equation representing the circle centered at (-27, 120) that passes through the origin is:

$(x + 27)^2 + (y - 120)^2 = 15129$

Solution:

The general equation of a circle is expressed as:

$(x-a)^2+(y-b)^2=r^2$

Where,

(a, b) denotes the center of the circle

r signifies the radius

Given the center as (-27, 120)

Thus;

a = -27

b = 120

Considering it intersects the origin, meaning (x, y) = (0, 0)

Substituting (a, b) = (-27, 120) and (x, y) = (0, 0) into the equation

$(0 + 27)^2 + (0 - 120)^2 = r^2\\\\729 + 14400 = r^2\\\\r^2 = 15129$

Input $r^2$ = 15129 and (a, b) = (-27, 120) into the equation

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1 month ago

Suppose the time interval between two consecutive defective light bulbs from a production line has a uniform distribution over a

lawyer [12517]

Answer:

a) The average of the time interval is 45 minutes.

b) There is a 27.78% chance that the time gap between two successive defective light bulbs will lie between 10 and 35 minutes.

c) The standard deviation for the time duration is 25.98 minutes.

d) There is an 11.11% likelihood that the time interval between two successive defective light bulbs will be under 10 minutes.

Step-by-step explanation:

A uniform probability situation occurs when all outcomes have an equal chance of happening.

In this context, we identify a lower and upper limit for the distribution known as 'a' and 'b', respectively.

The likelihood of finding a value X that is less than x is determined by this formula.

$P(X < x) = \frac{x - a}{b-a}$

The likelihood of obtaining a value X that lies between c and d is expressed as:

$P(c \leq X \leq d) = \frac{d-c}{b-a}$

The average of the uniform distribution is:

$M = \frac{a+b}{2}$

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$S = \sqrt{\frac{(b-a)^{2}}{12}}$

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This indicates that $a = 0, b = 90$

a) What is the mean of the time interval?

$M = \frac{a+b}{2} = \frac{0 + 90}{2} = 45$

The mean of the time interval is 45 minutes.

b) What is the probability that the time gap between two consecutive defective light bulbs will be between 10 and 35 minutes?

$P(10 \leq X \leq 35) = \frac{35-10}{90-0} = 0.2778$

There is a 27.78% chance that the time interval between two successive defective light bulbs falls between 10 and 35 minutes.

c) What is the standard deviation of the time interval?

$S = \sqrt{\frac{(90-0)^{2}}{12}} = 25.98$

The standard deviation of the time interval is 25.98 minutes.

d) What is the probability that the time interval between two consecutive defective light bulbs will be less than 10 minutes?

$P(X < 10) = \frac{10 - 0}{90 - 0} = 0.1111$

There is an 11.11% likelihood that the time duration between two consecutive defective light bulbs will be shorter than 10 minutes.

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1 month ago