The sum of two consecutive integers is one less than three times the smaller integer. Find the two integers

Greetings!

Let's denote the larger integer as L and the smaller one as s.

The relationship can be expressed as L=s+1

The sum of the integers can be described by the equation L+s=3s-1

Now, substituting L into the second equation allows us to isolate s.

s+1+s=3s-1

Combining like terms results in.

2s+1=3s-1

Subtracting 3s from both sides gives us.

-s+1=-1

Next, we can eliminate 1 from both sides.

-s=-2

Dividing both sides by -1 yields.

s=2

Hence, since these numbers are consecutive, the larger integer must be 3.

Thus, the integers we found are 2 and 3.

I hope this response is useful!

The two integers are 2 and 3