Answer: 4.85%
Step-by-step explanation: productivity = parcels delivered / count of drivers.
When the parcels delivered totaled 103,000, the average driver count was 84, resulting in productivity of
103,000 / 84 = 1226.19
In the instance when the parcels delivered amounted to 112,800, the mean number of drivers was 96, leading to a productivity of
112,800 / 96 = 1166.67
Consequently, the change in productivity is calculated as 1226.19 - 1166.67 = 59.52.
The initial productivity stands at 1226.19
the final productivity is 1166.67
The percentage change in productivity can be expressed as the change in productivity divided by initial productivity, multiplied by 100
% change in productivity = 59.52 / 1226 * 100
% change in productivity = 4.85%
When formulating the function accurately, it is crucial to properly designate the variables and comprehend the problem's context. Here, we will define y as the number of individuals and x as the number of songs performed.
At x = 0, y = 567
At x = 1, y = 567 - 567(1/3)
At x = 2, y = 567 - 567(1/3)(1/3)
At x = 3, y = 567 - 567(1/3)(1/3)(1/3)
Thus, the equation representing the number of individuals remaining after x songs is:
y = 567 - 567(1/3)x
y = 567(1 - x/3)
Answer:
900m
Step-by-step explanation:
A=wl
W=25
L=12
A=25 x 12
A= 300
300 meters x 3 laps = 900 meters walked
Y = 3x - 7...the slope here is 3 while the y-intercept is -7
3x + 9y = 9
9y = -3x + 9
y = -1/3x + 1....the slope of this line is -1/3 and the y-intercept is 1
the slopes 3 and -1/3 are negative reciprocals of one another...therefor, these lines are perpendicular.
Answer:
Step-by-step explanation:
First, we need to calculate how many potential credit card numbers can be created using the digits 0 through 9.
We aim to create a number that consists of 16 digits from a total of 10 digits, therefore:
The total count of possible numbers formed is 
. However, only 100 million of these are valid (
). Let n represent the valid number of combinations.
This leads us to the probability of selecting a valid number:
P(valid) = n / N
