Response:
B. 255 m
Detailed breakdown:
utilize similar triangles
L / 60 = 85 / 20
L = (85 * 60) / 20
L = 255 m
The characterization of HIJK as a parallelogram arises from the fact that the midpoints of both diagonals coincide at (1, 0), which indicates that these diagonals bisect each other. To explicitly demonstrate this, we determine that the midpoints of the diagonals HJ and IK are equal, confirming HIJK's properties as a parallelogram.
Response:
The average of the 10 sales figures for store A is $40,000.
Detailed explanation:
Provided;
yˆ= −3,000 + 1.2x...................... (1)
Where;
x = daily sales amounts at store A or the average of the 10 sales amounts for store A =?
yˆ = daily sales amounts at store B or the average of the 10 sales amounts for store B = $45,000
Substituting y = 45,000 into equation (1) and solving for x, yields:
45,000 = −3,000 + 1.2x
45,000 + 3,000 = 1.2x
48,000 = 1.2x
x = 48,000 / 1.2
x = 40,000
Consequently, the mean of the 10 sales figures for store A is $40,000.
Response:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) signifies the likelihood that a student with a visa card also possesses a MasterCard.
p(A/B) indicates the probability that a student with a MasterCard also has a visa card.
e. 0.35
f. 0.31
Detailed explanation:
a. p(AUBUC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.11 - 0.1 + 0.07 = 0.76
b. P(AnBnC') = P(AnB) - P(AnBnC)
= 0.3 - 0.07 = 0.23
c. P(B/A) = P(AnB)/P(A)
= 0.3/0.6 = 0.5
e. P((AnB)/C) = P((AnB)nC)/P(C)
= P(AnBnC)/P(C)
= 0.07/0.2 = 0.35
f. P((AUB)/C) = P((AUB)nC)/P(C)
= (P(AnC) U P(BnC))/P(C)
= (0.11 + 0.1)/0.2
= 0.21/0.2 = 0.31
Result: OPTION D.
Step-by-step reasoning:
The total cost for Lindy can be calculated employing the expression given in the task:
Here, "d" signifies the drinks ordered and "t" represents the toppings on a medium pizza she selects.
Since she and her friends order 4 drinks alongside a medium pizza that includes 3 toppings, you can derive the total cost by substituting these values into the provided expression.
The values are:
Upon substituting into the expression and performing the calculations, the result is:
