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Galina-37
2 months ago
13

in the drawing six out of every 10 tickets are winning tickets of the winning tickets one out of every three awards is a larger

prize what is the probability that a ticket is randomly chosen will award a larger prize
Mathematics
2 answers:
tester [12.3K]2 months ago
8 0

Answer: P(\text{a ticket is randomly chosen will award a large prize)}=\frac{2}{21}

Given that

Total tickets = 10

Winning tickets = 6

\text {Possibility of getting a winning ticket }=^{10}C_6

For every three prizes, there’s one large prize

therefore,

\text{ Possibility of getting a large prize }=^6C_3

At this point,

P(\text{a ticket is randomly chosen will award a large prize)}=\frac{^6C_3}{^{10}C_6}\\\\=\frac{20}{210}\\\\=\frac{2}{21}

P(\text{a ticket is randomly chosen will award a large prize)}=\frac{2}{21}

lawyer [12.5K]2 months ago
5 0
<span>To find the probability of drawing a winning ticket that yields a large prize, we can ascertain probabilities for each outcome. The chance of selecting a winning ticket is 6/10, and for those winning tickets, 1/3 represents a larger prize. This translates to 2 larger prizes for every 10. Hence, the probability that a selected ticket grants a larger prize is 2/10 or equivalently, 1/5</span>
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Answer:

The expression representing the sum of three times a number and six, over the difference of seven times that number and nine

Step-by-step explanation:

we have

\frac{3p+6}{7p-9}

Let

p  -----> the variable

we understand that

In the numerator we have (3p+6)

The statement that corresponds to this algebraic representation is "The sum of three times a number plus six"

The denominator is (7p-9)

The statement that corresponds to this algebraic representation is "The difference of seven times the number and nine"

therefore

The statement that represents this problem is "The sum of three times a number and six, divided by the difference of seven times the number and nine"

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