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Lerok
15 days ago
13

A statistician at a metal manufacturing plant is sampling the thickness of metal plates. If an outlier occurs within a particula

r sample, the statistician must check the configuration of the machine. The distribution of metal thickness has mean 23.5 millimeters (mm) and standard deviation 1.4 mm. Based on the two-standard deviations rule for outliers, which is the greatest thickness that would require the statistician to check the configuration of the machine?
Mathematics
1 answer:
babunello [3.6K]15 days ago
7 0

Answer: 26.3 mm

Step-by-step explanation:

The two-standard deviations rule for outliers states that any value lying outside two standard deviations from the average is considered an outlier.

Given that the Mean is 23.5 millimeters (mm) and the standard deviation is 1.4 mm

The maximum thickness that should be reviewed = mean + 2 (standard deviation)

= 23.5 + 2(1.4)

= 23.5 + 2.8

= 26.3 mm

therefore, the maximum thickness warranting machine configuration review by the statistician = 26.3 mm.

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A food truck operator has traditionally sold 75 bowls of noodle soup each day. He moves to a new location and after a week sees
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Answer:

The p-value for this test is 0.031. It should be interpreted as "There is a 96.9% likelihood that the actual average of soup sales at the new site exceeds 75 bowls it daily"

Step-by-step explanation:

The p-value"In hypothesis testing, the p-value, or probability value, represents the likelihood of obtaining test outcomes at least as extreme as the observed results, given that the null hypothesis holds true"

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13 days ago
Given the graph below, find PQ
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Answer:

P is located at (-5, -1) and Q is at (2, -5).

Step-by-step explanation:

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13 days ago
If container a holds 8 gallons of water and container b holds 12% more than container a, how many gallons of water does containe
AnnZ [3877]
8.96 gallons of water

To solve this question, you multiply the ratio of the volumes of container b to container a by the volume of container a. As container b has a greater volume than container a, the ratio will be greater than 1. In this scenario, it is 112% since it includes a 12% increase: 100% + 12% = 112%. Consequently, the volume of container b is calculated as 112% x 8 gallons = 8.96 gallons.
3 0
2 days ago
What are the eight-digit grid coordinates for benchmark 86 (circled in red)?
lawyer [4008]

Answer:

An eight-digit grid coordinate allows for precision within 10 meters.

Step-by-step explanation:

Grid coordinates are designed to direct accurately to a specific location by using a map that includes equally spaced vertical and horizontal lines, each assigned numbers to outline a place. The intersection of these vertical and horizontal lines has unique identifiers and creates small sections called grid squares.

The precision increases with the number of digits in the coordinate; an eight-digit designation gives accuracy to the nearest 10 meters.

3 0
8 days ago
Sarah can bicycle a loop around the north part of Lake Washington in 2 hours and 30 minutes. If she could increase her average s
Leona [4166]

Response:

The loop's length is roughly 49.58 km.

Step-by-step details:

Given:

Duration to cycle the loop = 2 hours and 30 minutes

It is known that;

60 minutes = 1 hour

30 minutes = 0.5 hour

therefore, 2 hours and 30 minutes = 2+0.5 = 2.5\ hrs

∴ Time to cycle the loop = 2.5 hours

Let 's' denote the cycling speed.

Denote the total loop distance as 'd'

From our understanding;

Distance equals speed times time.

Representing this as an equation we have;

d =2.5s \ \ \ \ equation \ 1

Given:

If her speed increased by 1 km/hr, the time taken around the loop would decrease by 7 minutes.

As a result, we can say;

Speed =s+1

The time then will be shortened by 7 minutes.

7 minutes = 0.12 hours

Consequently, time = 2.5 - 0.12 = 2.38

Again, Distance is calculated as speed times time.

This can be expressed with equations;

d =2.38(s+1) \ \ \ \ equation \ 2

The distances are equivalent in both scenarios, thus we will determine speed by equating the equations.

2.5s = 2.38(s+1)\\\\2.5s=2.38s+2.38\\\\2.5s-2.38s =2.38\\\\0.12s= 2.38\\\\s =\frac{2.38}{0.12} \approx 19.83\ km/hr

So, Speed = 19.83 km/hr

Loop length (d) = 19.83\times 2.5 = 49.58 \ km

Therefore, the loop length is approximately 49.58 km.

7 0
5 days ago
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