Suppose that the probability that a person books an airline ticket using an online travel website is 0.72. Consider a sample of

0.183. This problem addresses Binomial Probability. The formula is nCx × p^x × q^(n - x), where p = 0.72 and q = 1 - p = 0.28. With x representing the number of successes equal to 9 and n being 10, we are calculating the probability that at least nine out of ten people utilized an online travel website for booking. At least 9 out of 10 translates to x ≥ 9, so we calculate P(x ≥ 9) for x = 9 and x = 10. This leads to: P(x ≥ 9) = 10C9 × (0.72^9 × 0.28^(10 - 9)) + 10C10 × (0.72^10 × 0.28^(10 - 10)), resulting in approximately P(x ≥ 9) = 0.183.