Complete the formal proof of (~Q→~R)v(R&~Q) from no premises. The empty premise line is not numbered. Hint: there are longer

Answer:

The number of standard deviations above the mean is

Step-by-step explanation:

The question indicates that:

   The average weight of the corn ears from each farm is

   The standard deviation for the corn ears from Iowa is

   The standard deviation for the corn ears from Ohio is

  A randomly chosen ear of corn from Iowa weighs  x =  1.39 pounds

  The standardized score is  z = 1.645

  The weight of a randomly chosen ear of corn from Ohio measures  

In general, the standardized score of corn weight from Iowa can be mathematically defined as:

=>      

=>        

=>        

Conversely, the standardized score of corn weight from Ohio is expressed as:

=>      

=>        

=>      

A positive value indicates this quantity represents the number of standard deviations above the mean.

Response:

Part A

The best choice is;

b. y = 128(0.989)x + 72

Part B

Ella can consume the tea post 7:22

Detailed clarification:

Here, we observe the temperature variation with time represented in an exponential equation as follows;

Let the temperature at time x (measured in minutes) be y

Thus, y = a × mˣ + b

Where:

b = Curve shift or the limiting value of the decreasing exponential function as x → ∞

When y = 200, x = 0

This leads to 200 = a × m⁰ + c = a + c

Here, c represents the graph's shift, which is the temperature increase = final temperature = 72°F

Thus, a = 200 - 72 = 128°F

When y = 197, at x = 2 minutes

Thus, 197 = 128·m² + 72 =

m² = (197 - 72)/128 = 125/128

m = √(125/128) = 0.98821

Therefore, the exponential cooling equation is given by;

y = 128 × (0.98821)ˣ + 72

Hence the best choice is b. y = 128(0.989)x + 72

Part B

When the tea's temperature reaches 172°F, we have;

172 = 128 × (0.989)ˣ + 72

Thus, (0.989)ˣ = (172 - 72)/128 = 100/128 = 25/32

log(0.989)ˣ = log(25/32)

x·log(0.989) = log(25/32)

x = log(25/32)/log(0.989) = 22.32 minutes

Thus, Ella can consume the tea post 7:22.

Answer:

$391

Step-by-step explanation:

Answer:

The answer is

Step-by-step explanation:

After operating under these conditions for a period of 6 months, he selects a simple random sample of 15 days. He logs the hours he walked each day as tracked by his fitness monitor, alongside his recorded billable hours from a work application on his computer.

The calculated slope is -0.245

The number of samples is n = 15

The standard error is 0.205

The confidence level is 95

The significance level is (100 - 95)% = 0.05

The degrees of freedom is n - 2 = 15 - 2 = 13

Critical Value = 2.16 = [using excel = TINV (0.05, 13)]

Marginal Error = Critical Value * standard error

= 2.16 * 0.205

= 0.4428

Response:

0011100000

1010010001

0111001110

Detailed explanation:

Since the question is incomplete, here is the full question.

Assume the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Represent each of these sets using bit strings, where the ith bit indicates 1 if the element i is part of the set, and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

Thus, we need to convert a), b), and c) into bit strings.

To begin with, the number of items in the universal set determines the number of bits in the bit string.

Next, a 1 denotes the presence of an element both in the universal set and in the subset.

A 0 indicates that an element is absent from the subset but present in the universal set.

Therefore, we obtain:

a) Subset {3,4,5} = 0011100000  (As it contains 3 ones, it shows that only 3,4,5 are included in both the universal and the subset.

In the same way,

b) Subset {1, 3, 6, 10} = 1010010001

c) Subset {2, 3, 4, 7, 8, 9} = 0111001110