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suter
1 month ago
13

Which term best describes the object shown in black in the rhombus below?

Mathematics
2 answers:
PIT_PIT [12.4K]1 month ago
8 0
C......................................................
zzz [12.3K]1 month ago
4 0
I believe the answer is D. I’m not entirely certain, but that might be the correct choice.:)
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Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 + 2x +1?
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While the vertex of the function f(x) = x^2 is at (0, 0), the vertex of the function g(x) = x^2 + 2x + 1 is at (-1, 0).
Although both functions share the same y-coordinate, the x-coordinates differ. This indicates that g(x) = x^2 + 2x + 1 represents a horizontal shift of f(x) = x^2.
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Let c1(t) = eti + (sin(t))j + t3k and c2(t) = e−ti + (cos(t))j − 6t3k. Find the stated derivatives in two different ways to veri
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Answer:

i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

\frac{d}{dx}(e^x) = e^x

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

\frac{d}{dx}(e^x) = e^x

\frac{d}{dx}(sinx) = cosx\\\frac{d}{dx}(cosx) = -sinx

Next, differentiate with respect to 't'

\frac{d}{dt}c_{1}+ c_{2} } = e^ t i +cost j +3t^2 k - e^-t i - sintj -18t^2 k

By factoring out i, j, and k terms, we arrive at:

\frac{d}{dt}(C_{1} +C_{2} ) = i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

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2 months ago
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