While the vertex of the function f(x) = x^2 is at (0, 0), the vertex of the function g(x) = x^2 + 2x + 1 is at (-1, 0).
Although both functions share the same y-coordinate, the x-coordinates differ. This indicates that g(x) = x^2 + 2x + 1 represents a horizontal shift of f(x) = x^2.
It should be 94, I hope this provides assistance
Answer:


Step-by-step explanation:
Step 1:-
We have c1(t) = e^ t i + (sin(t))j + t³k
and c2(t) = e^−t i + (cos(t))j − 6t³k.
By adding c1(t) and c2(t):
c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k
Now, employing the derivative formula:


Next, differentiate with respect to 't'

By factoring out i, j, and k terms, we arrive at:
