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ale4655
1 day ago
5

Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 + 2x +1?

Mathematics
2 answers:
zzz [9K]1 day ago
8 0

we know that

The vertex of the function

f(x)=x^{2}

is indicated by the point (0,0)

and

the function

g(x)=x^{2} +2x+1

can be expressed as

g(x)=(x+1)^{2}

so

the vertex is determined at the point (-1,0)

therefore

the response is

The translation that relocates the vertex of f(x) to that of g(x) is defined by the following rule

(x,y)--------> (x-1, y)

check

(0,0)----> (0-1,0)----> (-1,0) is ok

PIT_PIT [9.1K]1 day ago
4 0
While the vertex of the function f(x) = x^2 is at (0, 0), the vertex of the function g(x) = x^2 + 2x + 1 is at (-1, 0).
Although both functions share the same y-coordinate, the x-coordinates differ. This indicates that g(x) = x^2 + 2x + 1 represents a horizontal shift of f(x) = x^2.
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17 days ago
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If f(x)=2x+1f(x)=2x+1f, left parenthesis, x, right parenthesis, equals, 2, x, plus, 1 and g(x)=x^2+7g(x)=x 2 +7g, left parenthes
Inessa [8989]

Answer:

The composite function;

f(g(x) = 2x^2 + 15

Step-by-step explanation:

Given f(x) = 2x + 1 and g(x) = x^2 + 7;

we are tasked with calculating f(g(x))

This represents a composite function where we substitute g(x) into f(x)

Consequently, we find

f(g(x)) = 2(x^2 + 7) + 1

f(g(x)) = 2x^2 + 14 + 1

f(g(x)) = 2x^2 + 15

5 0
1 month ago
There are 11 portable mini suites (a.k.a. cages) in a row at the Paws and Claws Holiday Pet Resort. They are neatly labeled with
AnnZ [9071]

Step-by-step explanation:

a) 7!

In absence of any restrictions, the answer is 7! as it represents the permutations of all animals.

b) 4! x 3!

Considering there are 6 cats and 5 dogs, the first and last slots must be occupied by cats to ensure alternate arrangements. The only options available then are based on the arrangement of the cats among themselves and the dogs among themselves, yielding 4! permutations for the cats and 3! for the dogs, thus leading to a total of 4! x 3! arrangements.

c) 3! x 5!

Here, the arrangement of the dogs among themselves can occur in 3! ways. Considering the dogs as a singular “object,” we can arrange this unit with the 4 cats, providing 5! total arrangements possible, leading to 3! · 5! arrangement possibilities.

d) 2 x 4! x 3!

In this scenario, both cats and dogs must be grouped together, allowing positions where all cats come before the dogs or vice versa. As there are two configurations, the resultant count is 2 multiplied by both arrangements, resulting in 2 x 4! x 3!

3 0
8 days ago
What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
Inessa [8989]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format y/x=k or y=kx

For this question, we have

the point (5,12) lies on the direct variation line

therefore

Determine the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

The equation is

y=\frac{12}{5}x

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point (0,0)

x=0\ y=0

Insert the values of x and y into the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is valid

thus

the point (0,0) lies on the direct variation line

case B) point (2.5,6)

x=2.5\ y=6

Insert the values of x and y into the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is valid

thus

the point (2.5,6) lies on the direct variation line

case C) point (3,10)

x=3\ y=10

Insert the values of x and y into the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not valid

thus

the point (3,10) does not lie on the direct variation line

case D) point (7.5,18)

x=7.5\ y=18

Insert the values of x and y into the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is valid

thus

the point (7.5,18) lies on the direct variation line

case E) point (12.5,24)

x=12.5\ y=24

Insert the values of x and y into the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not valid

thus

the point (12.5,24) does not lie on the direct variation line

case F) point (15,36)

x=15\ y=36

Insert the values of x and y into the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is valid

thus

the point (15,36) lies on the direct variation line

ultimately

the solution is

(0,0)

(2.5,6)

(7.5,18)

(15,36)


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8250-3120=5130

5130/75=68.40

Each member of the band has to contribute $68.40
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