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BabaBlast
1 month ago
13

In a certain country, a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of

an ounce) has an additional cost. The function below represents the cost of mailing one letter in this country. Josiah has two letters. The first weighs 2.9 ounces, and the second weighs 4.1 ounces. What is the total amount Josiah can expect to pay for postage?
Mathematics
2 answers:
Inessa [12.5K]1 month ago
8 0
Are there any multiple-choice options available?
tester [12.3K]1 month ago
7 0
The total postage is $1.84. To explain: a letter weighing up to 1 ounce costs $0.42 to send, and there are additional charges for each extra ounce (or fraction thereof). For Josiah's two letters, the fees are calculated based on their weights.
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Answer:

Refer to the explanation

Step-by-step explanation:

As approximately 10% of users fail to close Windows properly, we determine:

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2 months ago
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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
Svet_ta [12734]

We are given the triangle

△ABC, with m∠A=60° and m∠C=45°, and AB=8.

To start, we will calculate all angles and sides.

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The total of all angles in a triangle equals 180.

m∠A + m∠B + m∠C = 180.

Substituting the known values,

60° + m∠B + 45° = 180.

This gives us m∠B = 75°.

Calculating BC:

Using the law of sines,

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

We can substitute in the values.

\frac{8}{sin(45)}=\frac{BC}{sin(60)}

BC=\frac{8}{sin(45)} \times sin(60)

BC=9.798

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\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

Now we'll input the values.

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

AC=10.928

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We substitute values here as well.

p=10.928+8+9.798

p=28.726

Calculating Area:

Using the area formula,

A=\frac{1}{2}AB \times AC \times sin(A)

we can then insert values.

A=\frac{1}{2}8 \times 10.928 \times sin(60)

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Given that the parabola aligns with this requirement, its equation can be expressed as

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