Answer:
The y-intercept for line MN is 2
The standard form of the equation is revealed as ⇒ x + y = 2
Step-by-step elucidation:
Coordinates marking the ends of line MN → M(-3, 5) and N(2, 0)
The slope of the line was computed as 
= 
= -1
For line MN which passes through (-3, 5) with a slope of -1, the equation formulated is given by
y - 5 = (-1)(x + 3)
This simplifies to
y - 5 = -x - 3
Thus resulting in
y = -x + 2
Here the equation appears in the y-intercept form of
y = mx + b
where m represents the slope of the line and b denotes the y-intercept
So, consequently, the y-intercept for line MN is 2
The equation generates in the standard form as
x + y = 2
[[TAG_59]][[TAG_60]][[TAG_61]]
Response:
The factored expression 
is 
.
Detailed explanation:
Provided:
Our goal is to express the given equation in a factored form.
Factoring pertains to rewriting an expression so that the product of its factors yields the original expression
Let’s consider the expression .
We recognize the algebraic identity 
Thus, we have 
.
Matching with the above identity, we assign x= a, and b = 11, leading to
.
Consequently, the factored expression is .
Utilizing the Law of Sines (sinA/a=sinB/b=sinC/c) and recognizing that the angles in a triangle add up to 180°.
The angle C calculates to 180-53-17=110°
Thus, we have 27/sin53=b/sin17=c/sin110
This leads to b=27sin17/sin53, c=27sin110/sin53
The perimeter is defined as a+b+c, so
p=27+27sin17/sin53+27sin110/sin53 units
p≈68.65 units (rounded to the nearest hundredth of a unit)
This question is quite lengthy, so I will offer a brief overview. To find your x-value, set y to 0 in the given equation.
2x + 3y = 1470
2x + 3(0) = 1470
2x = 1470
x = 735
Thus, your farthest point on the x-axis is (735,0).
Now, repeat for y.
2x + 3y = 1470.
2(0) + 3y = 1470
3y= 1470
y= 490
Your highest point thus is (0,490).
After plotting both points, connect them with a straight line to illustrate your graph.
Check
Answer:
d) Both blocks experienced equivalent energy loss due to friction
Explanation:
As stated in the question, two tractors are pulling two identical stone blocks the same distance across similar surfacesAdditionally, block A moves at double the speed of block B when completing the race
This implies both blocks suffer from comparable friction loss
Moreover, we understand that
Energy loss from friction is 
Thus, the friction loss should be identical for both blocks
therefore, option d is the accurate choice 
