the Hog's head pub decide to make mixture thst is 50% butterbeer. how much of an 80% butterbeer solution should mixed with 20 ga

Question

vova2212

1 month ago

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the Hog's head pub decide to make mixture thst is 50% butterbeer. how much of an 80% butterbeer solution should mixed with 20 ga

llon of 20% butterbeer solution to create the new mixture?

Mathematics

1 answer:

Zina [12.3K] · Answer 1 · 2026-03-31T20:58:26+03:00

There are 20 gallons of a 20% butterbeer solution.
Let x represent the gallons of the 80% solution.

Thus, the total volume of the resulting solution will be (x+20) gallons
The final mixture needs to be 50% concentration.

Consequently, we can formulate the equation as:

$0.2(20)+0.8(x)=0.5(x+20) \\ \\ 4+0.8x=0.5x+10 \\ \\ 0.8x-0.5x=10-4 \\ \\ 0.3x=6 x=20$ .

Hence, to achieve a 50% butterbeer solution, 20 gallons of the 80% mixture should be combined with 20 gallons of the 20% mixture.