The result is 3.6y. By multiplying 0.3 by 12, we arrive at 3.6, and we include the variable y.
This represents a difference of squares:
(16a^4 - b^4)
= (4a^2 + b^2)(4a^2 - b^2)
Furthermore, the second bracket can be simplified as it is also a difference of two squares:
(4a^2 + b^2)(4a^2 - b^2)
= (4a^2 + b^2)(2a - b)(2a + b)
2x + 4
To represent 2x + 4, the following is required:
2 positive x-tiles corresponding to 2x.
4 positive unit tiles for the value of 4.
3x + (-1)
To illustrate 3x + (-1), you will need:
3 positive x-tiles to depict 3x.
1 negative unit tile to signify (-1).
In certain cases, a function necessitates multiple formulas to achieve the desired outcome. An example is the absolute value function \displaystyle f\left(x\right)=|x|f(x)=∣x∣. This function applies to all real numbers and yields results that are non-negative, defining absolute value as the magnitude or modulus of a real number regardless of its sign. It indicates the distance from zero on the number line, requiring all outputs to be zero or greater.
<pwhen inputting="" a="" non-negative="" value="" the="" output="" remains="" unchanged:="">
\displaystyle f\left(x\right)=x\text{ if }x\ge 0f(x)=x if x≥0
<pwhen inputting="" a="" negative="" value="" the="" output="" is="" inverse:="">
\displaystyle f\left(x\right)=-x\text{ if }x<0f(x)=−x if x<0
Due to the need for two distinct operations, the absolute value function qualifies as a piecewise function: a function defined by several formulas for different sections of its domain.
Piecewise functions help describe scenarios where rules or relationships alter as the input crosses specific "boundaries." Business contexts often demonstrate this, such as when the cost per unit of an item decreases past a certain order quantity. The concept of tax brackets also illustrates piecewise functions. For instance, in a basic tax system where earnings up to $10,000 face a 10% tax, additional income incurs a 20% tax rate. Thus, the total tax on an income S would be 0.1S when \displaystyle {S}\leS≤ $10,000 and 1000 + 0.2 (S – $10,000) when S > $10,000.
</pwhen></pwhen>
Answer:
a. 0.68 or 68%
b. 0.08 or 8%
c. 0.32 or 32%
Step-by-step explanation:
The probability of contacting the client on the first call is 60%
The likelihood of reaching the client on the second call is 20%
a. The chance of the manager successfully connecting with her client within two calls is the sum of the chances for one or two calls:
b. The probability that the manager connects during the second call but not the first is:
c. The probability that the manager fails to connect in two consecutive calls (requiring more calls) is P(X>2):
