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Sonbull
4 months ago
8

A piece of iron metal is heated to 155 degrees C and placed into a calorimeter that contains 50.0 mL of water at 18.7 degrees C.

The temperature of the water rises to 26.4 degrees C. How much heat was released by the iron?
A-1610 J
B-5520 J
C-385 J
D-2250 J
Chemistry
2 answers:
VMariaS [2.9K]4 months ago
3 0
Jsjsjsdjdjkdskkeekdks probably answer a
alisha [2.9K]4 months ago
0 0

It's option A; I'm just uncertain about how. But it's definitely option A.

You might be interested in
What mass of water in grams will fill a tank 100 cm long, 50 cm wide, and 30 cm high? Knowing that the density of water is 1 g/m
castortr0y [3046]

The mass is 150,000 grams. Multiply 100 by 50 by 30 to determine the container's volume, which equals 150,000 cm^3. Since a milliliter is equivalent to one cubic centimeter, and given that the density of water is one gram per milliliter, it follows that the mass of water is 150,000 grams.

7 0
2 months ago
Sodium only has one naturally occuring isotope, 23 Na , with a relative atomic mass of 22.9898 u . A synthetic, radioactive isot
KiRa [2933]

Answer:

The mass of 22-Na included in the sample amounts to 0.0599 g

Explanation:

The total mass of the isotope mixture is 1.8385g.

It has an apparent mass of 22.9573 u.

For 23-Na, the relative atomic mass is 22.9898 u, while for 22-Na it is 21.9944 u.

Let the relative abundance of 23-Na be denoted as X.

This means that the relative abundance of 22-Na can be expressed as (1-X).

The equation formed is 21.9944 (1-X) + 22.9898 X = 22.9573.

Rearranging gives: 21.9944 - 21.9944X + 22.9898X = 22.9573.

Which simplifies to 22.9898X - 21.9944X = 22.9573 - 21.9944.

Hence, 0.9954X = 0.9639, leading to X = 0.9674.

The relative abundance of 23-Na is now identified as 0.9674.

Consequently, the relative abundance of 22-Na is 1 - 0.9674 = 0.0326.

Now, the mass of 22-Na contained within the 1.8385g sample is determined by

Relative abundance of 22-Na multiplied by the mass of the total sample = 0.0326 × 1.8385g = 0.0599 g.

6 0
4 months ago
1. If a car is traveling 90 mi/hr, how many feet will the car travel in 1 sec? In 5 sec?
alisha [2963]

Answer:

The vehicle travels 660 feet

Explanation:

Initially, convert the speed into Feet per second

The car's speed is 90 mi/hr

1 mi = 5280 ft

For 90 miles, we calculate 90 x 5280 = 475,200 feet

1 hour = 60 minutes

1 minute = 60 seconds

Therefore,

1 hour = 60 x 60 seconds = 3600 seconds

Speed is defined as the distance covered by an object over time. The speed formula is:

Speed =\frac{distance}{time}

Speed =\frac{90mi}{1hr}... given

Speed =\frac{475200 ft}{3600sec}

Speed = 132 ft/sec

Thus,  time = 5 seconds

Speed =\frac{distance}{time}

distance =speed\times time

distance = 132ft/sec\times 5sec

Distance = 660 feet

3 0
3 months ago
Ibuprofen, a headache remedy, contains 75.69% C, 8.80% H, and 15.51% O by mass and has a molar mass of 206 g/mol. Express your a
castortr0y [3046]

Answer:

A) The molecular formula for ibuprofen isC_{13}H_{18}O_2

B) The molecular formula for Cadaverine is C_{5}H_{14}N_2

C) The molecular formula for Epinephrine is C_9H_{13}O_3N_1

Explanation:

Element percentage in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100

A) The composition of ibuprofen, used for headaches, consists of 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by weight.

Ibuprofen has a molar mass of 206 g/mol.

The proposed molecular formula for ibuprofen is =C_xH_yO_z

Count of carbon atoms in one ibuprofen molecule;

75.69\%=\frac{x\times 12 g/mol}{206 g/mol}\times 100

x=\frac{75.69\times 206 g/mol}{100\times 12 g/mol}=12.99\approx 13

Count of hydrogen atoms in one ibuprofen molecule;

8.80\%=\frac{y\times 1 g/mol}{206 g/mol}\times 100

y=\frac{8.80\times 206 g/mol}{100\times 1 g/mol}=18.12\approx 18

Count of oxygen atoms in one ibuprofen molecule;

15.51\%=\frac{z\times 16 g/mol}{206 g/mol}\times 100

z=\frac{15.51\times 206 g/mol}{100\times 16 g/mol}=1.99\approx 2

Molecular formula for ibuprofen:

= C_xH_yO_z= C_{13}H_{18}O_2

B) Cadaverine consists of 58.55% carbon, 13.81% hydrogen, and 27.40% nitrogen by weight

Cadaverine has a molar mass of 102.2 g/mol.

The proposed molecular formula for Cadaverine is =C_xH_yN_z

Count of carbon atoms in one Cadaverine molecule;

58.55\%=\frac{x\times 12 g/mol}{102.2 g/mol}\times 100

x=\frac{58.55\times 102.2 g/mol}{100\times 12 g/mol}=4.98\approx 5

Count of hydrogen atoms in one Cadaverine molecule;

13.81\%=\frac{y\times 1 g/mol}{102.2 g/mol}\times 100

y=\frac{13.81\times 102.2 g/mol}{100\times 1 g/mol}=14.11\approx 14

Count of nitrogen atoms in one Cadaverine molecule;

27.40\%=\frac{z\times 14 g/mol}{102.2 g/mol}\times 100

z=\frac{27.40\times 102.2 g/mol}{100\times 14 g/mol}=2.00\approx 2

Molecular formula for Cadaverine:

= C_xH_yN_z= C_{5}H_{14}N_2

C) Epinephrine includes 59.0% carbon, 7.1% hydrogen, 26.2% oxygen, and 7.7% nitrogen by weight

Epinephrine has a molar mass of 180 g/mol.

The proposed molecular formula for Epinephrine is =C_xH_yO_zN_w

Count of carbon atoms in one Epinephrine molecule;

59.0\%=\frac{x\times 12 g/mol}{180 g/mol}\times 100

x=\frac{59.0\times 180 g/mol}{100\times 12 g/mol}=8.85\approx 9

Count of hydrogen atoms in one Epinephrine molecule;

7.1\%=\frac{y\times 1 g/mol}{180 g/mol}\times 100

y=\frac{7.1\times 180 g/mol}{100\times 1 g/mol}=12.78\approx 13

Count of oxygen atoms in one Epinephrine molecule;

26.2\%=\frac{z\times 16 g/mol}{180 g/mol}\times 100

z=\frac{26.2\times 180 g/mol}{100\times 16 g/mol}=2.94\approx 3

Count of nitrogen atoms in one Epinephrine molecule;

7.7\%=\frac{w\times 14 g/mol}{180 g/mol}\times 100

w=\frac{7.7\times 180 g/mol}{100\times 14 g/mol}=0.99\approx 1

Molecular formula for Epinephrine:

= C_xH_yO_zN_w= C_9H_{13}O_3N_1

7 0
4 months ago
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