Answer:
The heat capacity of the calorimeter is 
= 54.4 
Explanation:
Given the data
Heat supplied Q = 4.168 KJ = 4168 J
Mass of water 
= 75.40 gm
Change in temperature = ΔT = 35.82 - 24.58 = 11.24 °C
From the conditions provided
Q = 
ΔT + ΔT
Plugging all values into the above equation yields
4168 = 75.70 × 4.18 × 11.24 + × 11.24
611.37 = × 11.24
= 54.4
This represents the heat capacity of the calorimeter.
Hi there! Calvin informed Marie that they could still incorporate solute until reaching 40 grams because the solution remained unsaturated. Unsaturated solutions denote situations where the solvent (water in this instance) can further dissolve more solute (here, KNO₃) considering the current pressure and temperature. This can be visually confirmed when additional solute does not lead to visible solid residues settling at the bottom of the flask, indicating that the dissolving rate surpasses the crystallization rate. Wishing you a pleasant day!
