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Evgen
14 days ago
12

How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space

Chemistry
2 answers:
VMariaS [2.6K]14 days ago
7 0

Answer:

The gas pressure equals 1.40 atm

Explanation:

This problem can be resolved using the Ideal Gas Law:

P. V = n. R.T

T° = 370K

V = 17.3L

n = 0.8 mol

Let's insert the data → P. 17.3L = 0.8 mol. 0.082L.atm/mol.K. 370K

Thus, P = (0.8 mol. 0.082L.atm/mol.K. 370K) / 17.3L = 1.40 atm

KiRa [2.7K]14 days ago
3 0

Answer:

The pressure measures 1.40 atm

Explanation:

Step 1: Provided data

Moles = 0.8 moles

Temperature = 370 K

Volume = 17.3 L

Step 2: Pressure calculation

p*V = n*R*T

⇒ where p = pressure = TO BE DETERMINED

⇒ with V = volume = 17.3 L

⇒ with n = number of moles = 0.8 moles

⇒ with R = gas constant = 0.08206 L*atm/mol*K

⇒ with T = temperature = 370 K

p = (n*R*T)/V

p = (0.8 * 0.08206 * 370) / 17.3 L

p = 1.40 atm

The pressure measures 1.40 atm

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