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Stella
8 days ago
15

If 32.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

Chemistry
1 answer:
alisha [2.8K]8 days ago
6 0
To calculate the moles of MgSO4.7H2O, we find the molar mass equals 246, thus moles = 32 / 246 = 0.13 moles. Upon heating, all 7 H2O from one molecule will evaporate. The total moles of H2O present amount to 7 x 0.13 = 0.91, and the mass of that H2O is 0.91 x 18 = 16.38g. Therefore, the mass of the anhydrous MgSO4 that remains is 32 - 16.38 = 15.62 g.
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Infrared spectroscopy is a useful tool for scientists who want to investigate the structure of certain molecules. Which of the f
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Answer: The energies of infrared photons are comparable to those linked with various vibrational states of chemical bonds. Molecules can absorb infrared photons of specific wavelengths, highlighting the types and strengths of different chemical bonds present within the molecules.

Explanation:

Infrared spectroscopy evaluates the vibrational energy states found in molecules. When a molecule absorbs infrared photons, the chemical bonds vibrate at distinct frequencies. Scrutinizing the alterations in vibrational energy within a molecule allows for the identification of different bond types and consequently the molecule’s general structure. The vibrational behaviors of a molecule encompass bending, stretching, and scissoring motions.

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A 3.0-L sample of helium was placed in container fitted with a porous membrane. Half of the helium effused through the membrane
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Explanation:

The rate at which gases effuse is inversely related to the square root of their molar masses.

In this case, half of the helium (1.5 L) passed through the membrane in 24 hours. Therefore, we can calculate the effusion rate of He gas as follows.

          \frac{1.5 L}{24 hr}

            = 0.0625 L/hr

Given that the molar mass of He is 4 g/mol and for O_{2} it is 32 g/mol.

Now,

   \frac{\text{Rate of He}}{\text{Rate of Oxygen}} = \sqrt{\frac{32}{4}

                               = 2.83

Thus, the effusion rate of O_{2} = \frac{\text{Rate of He}}{2.83}

                       = \frac{0.0625 L/hr}{2.83}

          Rate of O_{2} = 0.022 L/hr.

This implies that 0.022 L of O_{2} gas will effuse in one hour.

Consequently, to find the duration needed for 1.5 L of O_{2} gas to effuse, we calculate as follows.

         \frac{1.5 L}{0.022 L/hr}

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Thus, we can conclude that it will require 68.18 hours for half of the oxygen to effuse through the membrane.

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27 days ago
A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state.Th
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The answer is C. The specific amount of energy released when excited electrons fall back to the ground state produces an emission spectrum. That energy is emitted as photons with precise wavelengths corresponding to the energy differences between levels. Because each element yields a characteristic set of wavelengths, the emission spectrum can be used to identify the element in the sample.
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16 days ago
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Answer:

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The sample solution might be tainted.

Explanation:

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The testing solution could also be contaminated, causing it to display a color different from the anticipated shade of the test ion.

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