Mario walked at a rate of 2/3 miles every 10 minutes what is his unit rate every mile per hour

Without specific options available, I can provide guidance on where to focus your attention.

The end behavior of a function refers to how the graph behaves (upwards or downwards) as it nears positive or negative infinity within its domain. Essentially, we’re investigating the direction the graph tends towards on both sides.

In this scenario, as the value of x grows, the graph descends, while it ascends when x diminishes. Seek out a comparable occurrence.

The equation of the perpendicular line can be identified by determining its slope and applying the given point within the standard formula.

Standard equation: y-y1 = m(x-x1)

m*m'=-1
where m' indicates the slope of the perpendicular line
m denotes the slope of the original line

m = -coefficient of x/coefficient of y = -4/-3 = 4/3
m' = -3/4

Substituting the point (3, -2):
y+2 = -3/4*(x-3)
4y+8 = -3x+9

Thus, the equation of the perpendicular line is: 3x+4y-1=0

Congruent angles have the same measurement.

Let’s evaluate the provided pairs one by one.

A. ∠MKR and ∠OAR

In the diagram, it’s visible that the angle bisector of the right-angled vertices creates angles MKR and OAR.

Thus, they are congruent measuring 45°

B. ∠ONT and ∠MTN

From the diagram, MTN forms a right angle, while ONT is created by bisecting this right angle.

Hence, these angles are not congruent with ∠MTN at 90° and ∠ONT at 45°

C. ∠IRS and ∠MRO

In the diagram, MRO is a right-angle, while IRS results from the bisection of the right angle.

Accordingly, these angles are not congruent with ∠MRO equal to 90° and ∠IRS at 45°

D. ∠URC and ∠TRO

In the diagram, it’s shown that the angle bisector of the right-angled vertices forms angles URC and TRO.

Thus, they are congruent, both measuring 45°

Therefore, the pairs of congruent angles are

A. ∠MKR and ∠OAR and D. ∠URC and ∠TRO

To resolve this issue, you simply multiply base 1 by height 1, which equals base 2 multiplied by height 2. Inserting our values yields 24 * 4 = 5 * height 2. By solving, we find the missing height to be 19.2. 

Answer:

Step-by-step explanation:

a) According to the included image, the smaller section measures 16ft², and the larger section is 50 ft². The formula for the area of a square is side × side = side².

For the smaller section: Area = side²

16 = side²

side = √16 = 4 ft

For the larger section: Area = side²

50 = side²

side = √50

The overall length of the shed is the small area plus the large area = 4 + √50

The total length of the shed equates to 4 + √50

b) All square roots of integers unless they are perfect squares are irrational numbers, thus 4 + √50 is irrational. All such values fall within the set of real numbers, categorizing  4 + √50 as an irrational and real number.