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Pani-rosa
1 month ago
7

400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis tes

t to check whether this represents a statistically significant difference from 50%, and use a significance level of 0.01.
Mathematics
1 answer:
babunello [11.8K]1 month ago
3 0

Answer:

The sample proportion shows a statistically significant divergence from 50%

Step-by-step explanation:

Null hypothesis: The sample proportion equals 50%

Alternative hypothesis: The sample proportion does not equal 50%

z = (p' - p) ÷ sqrt[p(1 - p) ÷ n]

p' is the sample proportion = 289/400 = 0.7225

p is the population proportion = 50% = 0.5

n is the number of students surveyed = 400

z = (0.7225 - 0.5) ÷ sqrt[0.5(1 - 0.5) ÷ 400] = 0.2225 ÷ 0.025 = 8.9

The analysis is two-tailed. At a significance level of 0.01, the critical value is 2.576. The acceptance region for the null hypothesis is between -2.576 and 2.576.

Conclusion:

Reject the null hypothesis since the calculated z-score of 8.9 is beyond the bounds established by the critical values of -2.576 and 2.576.

There is compelling evidence to support the assertion that the sample proportion signifies a meaningful difference from 50%.

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The result is $15,625

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the moon is 240,000 miles from earth what is the distance written as a whole number multiplied by the power of ten
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18 days ago
Before the last school year began, it was estimated that the average discretionary personal expenses each school year for a stud
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Answer:

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The mean is defined as the average expense value, calculated as follows:

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2.) Is the average higher or lower than the estimate?

Given the estimate of $2,110, the average is indeed higher than this estimate.

3.)What amount of personal expenses would Ashley need to maintain a combined average of $2,110 with her friends' amounts for that school year?

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Her needed amount of expenses would be $1,625.00.

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