The Green family is a family of six people. They have used 4,885.78 gallons of water so far this month. They cannot exceed 9,750

Question

9 days ago

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The Green family is a family of six people. They have used 4,885.78 gallons of water so far this month. They cannot exceed 9,750

.05 gallons per month during drought season. Write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month.

Mathematics

2 answers:

babunello [11.4K] · Answer 1 · 2026-04-01T10:00:40+03:00

Each family member can consume x = 810.71 gallons of water for the remaining month. The established equation is 6x + 4885.78 ≤ 9750.05. Here’s the detailed breakdown: The total members in the Green family add up to 6. Assuming one member utilizes x gallons, then six members will use a combined total of 6x gallons. Given that the Green family can only use a maximum of 9750.05 gallons monthly, and they have already consumed 4885.78 gallons, we derive the equation: 6x + 4885.78 ≤ 9750.05 This simplifies to: 6x ≤ 9750.05 - 4885.78 6x ≤ 4864.27 x ≤ 4864.27 / 6 x ≤ 810.71 gallons Thus, the derived equation is 6x + 4885.78 ≤ 9750.05, indicating that each member may use 810.71 gallons for the rest of the month.

Zina [12.1K] · Answer 2 · 2026-04-01T09:58:58+03:00

Zina [12.1K]9 days ago

3 0

The inequality is x ≤ (9750.05 - 4885.78)/6. This represents the amount of water a single family member may utilize for the remainder of the month.