M∠ rst + m∠ vst = 180°
3 x + 7° + 9 x + 17° = 180°
12 x + 24° = 180°
12 x = 180° - 24°
12 x = 156°
x = 156°: 12
x = 13°
m ∠ rst = 3 · 13° + 7° = 39° + 7° = 46°
m ∠ vst = 180° - 46° = 134°
Answer:
A ) 46° and 134°
La familia Freeman:
13 c/kWh (400 kWh) + 2 c/kWh (400 kWh) + 14.5 c/kWh) 450 kWh
= 6464.5 c
6464.5 c x 30 = 193935
La familia Baum:
8.5 (400) + 12 (400) + 14.5 (450)
= 14725 c
<span>La familia Freeman tiene un costo de $260.83 más que la familia Baum.
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<span>Skewness serves as a descriptive statistic in the analysis of data distribution. In the realm of finance and investing, skewness is considered alongside other statistics such as kurtosis and value at risk (VAR). When assessing investment returns, skewness reflects the asymmetry present in these returns. Normally distributed data sets will have a skewness of zero, whereas investment returns frequently deviate from a normal distribution.
In graphs showcasing investment returns displaying positive skewness, this indicates that: mean > median > mode. Conversely, a negative skewness reveals the relationship: mean < median < mode.
Evaluating skewness is crucial in reviewing investment returns, as it signals potential risks based on historical return patterns. Despite a negative skew indicating a high occurrence of smaller gains, it can also alert to the chance, albeit remote, of an extremely adverse outcome.</span>
Let h units denote the hypotenuse of the smaller triangle. From the Pythagorean Theorem, we derive specific relationships involving the smaller triangle with dimensions
along with the shorter leg of the second triangle denoted as s units. Furthermore, we apply the double angle property and substitute values to arrive at the final calculation.
Answer:

Step-by-step explanation:
It is known that the mean and standard deviation of the sampling distribution of the sample proportion(
) are represented as follows:-

, where p= Population proportion and n = sample size.
Let p denote the proportion of blue chips.
According to the information provided, we have
p= 0.275
n= 5
Thus, the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5 will be:

Therefore, you will have the mean and standard deviation for the sample proportion of blue chips for samples of size 5:
