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2 months ago

A new moon is discovered orbiting Neptune with an orbital speed of 9.3 103 m/s. Neptune's mass is 1.0 1026 kg. What is the

1 answer:

3 0

The radius of the moon's orbit is calculated as R = 7.715 x 10⁷ m, and the moon's orbital period is T = 14.48 hr. The given orbital speed of the moon is v = 9.3 x 10³ m/s, with Neptune's mass being M = 1.0 x 10²⁶ Kg. The moon's orbital velocity can be expressed using the formula. Therefore, by squaring the equation and resolving for r + h, we calculate: R = GM / v². Upon substituting in, we find R to be 7.715 x 10⁷ m. The relation for the moon's orbital period yields T = 2π/ω and simplistically, T = 2πR/v, where ω = v/r. Following this, we compute T, leading to the conclusion: T = 14.48 hr.

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Which new process was added to the nebular theory of solar system formation to account for the existence of Jupiter-mass planets

serg [3582]

Intense activity and magnetic fields are manifested by features, with sunspots occurring that are vastly larger than those seen on the Sun. These cause disturbances in the star's spectrum that exceed those produced by planets, rendering them significantly more difficult to detect, even in cases of hot Jupiters.

7 0

2 months ago

Two loudspeakers 42.0 m apart and facing each other emit identical 115 Hz sinusoidal sound waves in a room where the sound speed

ValentinkaMS [3465]

Answer:

She will be located in a loud area.

Explanation:

To evaluate whether Susan is situated in a quiet or loud area, we must first ascertain the difference in the sound waves reaching her from the two speakers.

If we refer to d₁ as the distance to speaker A, which measures 19.5 m, then d₂ to the other speaker is calculated as follows:

d₂ = 42.0 m - 19.5 m = 22.5 m

This reveals that the path difference between both speakers is:

d = d₂-d₁ = 22.5 m -19.5 m = 3.0 m

Next, we relate this distance to the sound wave's wavelength; for constructive interference, the path difference must equal an even multiple of half the wavelength:

d = (2n)*(λ/2)

To determine λ, we know that for any wave, the relationship between speed, frequency, and wavelength holds:

v = λ*f

λ = v/f = 345 m/s / 115 (1/s) = 3.0 m.

Since the difference between the distances to Susan from both speakers corresponds exactly to one wavelength, this indicates that both waves arrive at the same phase, resulting in constructive interference, thus labeling it as a loud area.

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5 0

3 months ago

Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric fi

Ostrovityanka [3204]

Let A represent the area of each plate. According to Gauss's Law, the electric field present between the plates can be derived.

8 0

2 months ago

Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.

kicyunya [3294]

Result:

$v=\sqrt{k\frac{e^2}{m_e r}}$ , $2.18\cdot 10^6 m/s$

Explanation:

The electromagnetic attraction between the electron and the proton in the nucleus is equivalent to the centripetal force:

$k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}$

where

k represents the Coulomb constant

e denotes the charge of the electron

e denotes the charge of the proton in the nucleus

r signifies the distance from the electron to the nucleus

v indicates the velocity of the electron

is the mass of the electron

Rearranging for v, we determine

$v=\sqrt{k\frac{e^2}{m_e r}}$

Inside a hydrogen atom, the distance separating the electron from the nucleus is roughly

$r=5.3\cdot 10^{-11}m$

while the mass of the electron is

$m_e = 9.11\cdot 10^{-31}kg$

and the charge is

$e=1.6\cdot 10^{-19} C$

By plugging in the values into the formula, we achieve

$v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s$

7 0

2 months ago

Two charges q1 = 5 µC, q2 = -26 µC, are L = 19 cm apart. A third charge is to be placed on the line between the two charges. How

Keith_Richards [3271]

The electric force between two objects is expressed as being proportional to the product of their charges and inversely proportional to the square of the distance separating them. In this instance, the distance between the first two charges is 19 cm. We formulate the equation k q1 q3/ (x)^2 = k q2 q3/ (19-x)^2, where x denotes the separation between q1 and q3. The charge q3 cancels out, and q2 is used in absolute terms. The resulting value of x is 5.79 cm.

6 0

2 months ago