3. In what possible scenario would the female birds evolve to having the singing trait? (5 points)

Euglena presenta un color verde gracias al clorofila que se encuentra en los cloroplastos de este organismo, y la estructura corporal situada en su base se llama flagelo.

Explanation:

Las Euglenas son especies que habitan en aguas dulces y saladas, y se encuentran en gran cantidad en cuerpos de agua interiores, donde pueden proliferar y teñir la superficie del agua de zanjas y estanques de un color verde.

Este color verde que producen se debe en gran parte a la clorofila que se halla en sus cloroplastos, la cual es el pigmento responsable del color verde. Este pigmento también es el causante de la coloración en este caso.

Las Euglenas cuentan con una estructura corporal especializada, ubicada en la base de su cola, que les permite moverse.

Esta estructura especializada se denomina flagelo.

Response:

Identify the primary concept

Explanation:

Different allele frequencies are expected in the two groups.

North American:

72 birds altogether => 144 total alleles

From 72, 55 birds have short plumes, hence 17 are short-plumed.

q^2 = (2*17) / 114 = 0.236

Frequency(short plume allele) = q = 0.486

Frequency(long plume allele) = p = 1 - q = 0.514

Thus, from the North American group:

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds totaling => 504 alleles

Out of 252 birds, 75 have long plumage, 177 are short-plumed.

q^2 = (2*177) / 504 = 0.702

Frequency(short plume allele) = q = 0.838

Frequency(long plume allele) = p = 1 - q = 0.162

Thus, from this South American group:

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

For the combined population:

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population reflects the p and q from this blended result. It consists of 1000 individuals. The share of long plumed birds will be the sum of homozygous long plumed and heterozygous long plumed, calculated as: p^2 + 2pq, which you multiply by the population count of 1000 for the outcome.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (final result)

To explore if substance A influences the reaction rate of the colored liquids X and Y, the researcher should first record the duration it takes for the mixture to clear when X and Y are combined. Next, he should assess how long it takes for the same result after incorporating substance A into the mixture of X and Y. This will help establish if substance A serves as an enzyme.

The answer is C. This conclusion is drawn from the understanding that roan coat coloration arises in heterozygous offspring produced by homozygous red and white parents, thereby nullifying option A, which involves two red parents. In B, the cross between CRCR and CRCW generates two roan and two red offspring but no white - eliminating that as a viable option. Option D, involving red and white homozygous parents, solely produces roan offspring. In option E, a cross of CWCW with CRCW yields two roan and two white but no red. Thus, option C remains valid as the cross of CRCW with CRCW results in 1 red, 2 roan, and 1 white offspring, matching the desired ratio.