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slava
6 days ago
7

Which two factors most influenced the growth of the Internet during the 1970s?

Computers and Technology
2 answers:
oksian1 [849]6 days ago
8 0

Answer:

The correct answer is "an increase in the influence of public universities along with a growing appreciation for a liberal arts education." The roles of DARPA and Russia were irrelevant here. Indeed, while advancements in computer hardware contributed to the expansion, federal funding from the National Science Foundation in 1981 is also not the right selection. Furthermore, electrical power supply is unrelated to this matter. Therefore, the aforementioned statement stands. The concept of the internet hinges on the principles of liberal arts education, imparting both practical and intellectual abilities and fostering social responsibility among global citizens. Additionally, public universities significantly impacted this development, a fact confirmed by the Pentagon when the issue of nuclear attack risks was raised.

Contrary to many who believe that the nuclear threat was the primary driver, it was not. In fact, this marked an era of liberalization, empowering public universities to disseminate various information types leading to the internet's expansion.

Explanation:

The response is quite clear from context.

ivann1987 [982]6 days ago
5 0

Answer:

The two key factors affecting the internet's growth in the 1970s are the enhanced power of computer hardware and augmented financial support from the National Science Foundation.

Explanation:

Initially, I selected the response outlined above, but upon reviewing it, I found the provided explanation compelling and thought they might be correct. However, that interpretation was not accurate. Ultimately, my initial selection remains valid as stated above.

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Write a program that prompts the user for an integer, then asks the user to enter that many values. Store these values in an arr
Rzqust [962]

Answer:

//To facilitate user input, the Scanner class is imported

import java.util.Scanner;

//The Solution class is being defined

public class Solution {

   //The main method is declared here, marking the start of program execution

   public static void main(String args[]) {

       

       //A Scanner object named 'scan' is instantiated to gather user input

       Scanner scan = new Scanner(System.in);

       //User is prompted to specify the size of the array

       System.out.print("Enter the range of array: ");

       //The user input is stored in arraySize

       int arraySize = scan.nextInt();

       //Initialization of userArray with the size specified by arraySize

       int[] userArray = new int[arraySize];

       

       //A counter is initialized to track the number of elements entered in the array

       int count = 0;

       //The following while loop will continue until the user finishes inputting the elements of the array

       while (count < arraySize){

           System.out.print("Enter each element of the array: ");

           userArray[count] = scan.nextInt();

           count++;

       }

       

       //A blank line is outputted for better readability

       System.out.println();

       

       //A for loop iterates to print all elements of the array in a single line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

       

       //Another blank line is printed for clarity

       System.out.println();

       

       //A for loop is utilized to reverse the contents of the array

       for(int i=0; i<userArray.length/2; i++){

           int temp = userArray[i];

           userArray[i] = userArray[userArray.length -i -1];

           userArray[userArray.length -i -1] = temp;

       }

       

       //A for loop prints each element of the reversed array in one line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

     

   }

}

Explanation:

The program is annotated to provide a thorough explanation.

The for-loop responsible for reversing the array operates by splitting the array into two segments and swapping elements from the first segment with those from the second segment. During each loop, an element from the first segment is temporarily stored in temp variable, and then that element is replaced with the corresponding element from the second segment. Subsequently, the element from the second segment is updated with the value held in temp.

3 0
25 days ago
Exercise 8.1.9: Diving Contest Your school is hosting a diving contest, and they need a programmer to work on the scoreboard! Yo
zubka84 [1007]

Response:

def calculate_score(theTuple):

    first, second, third = theTuple

    if first >= 0 and first <=10 and second >= 0 and second <=10 and third >= 0 and third <=10:

         print(first + second + third)

    else:

         print("Range must be 0 to 10")

Clarification:

This line initiates the function

def calculate_score(theTuple):

This line extracts the values used in the function

    first, second, third = theTuple

The subsequent if statement verifies whether the values fall within the 0 to 10 range

    if first >= 0 and first <=10 and second >= 0 and second <=10 and third >= 0 and third <=10:

This computes the total score

         print(first + second + third)

else:

Should the scores be outside the 0 to 10 limits, this line will be executed

         print("Range must be 0 to 10")

4 0
25 days ago
#Write a function called "angry_file_finder" that accepts a #filename as a parameter. The function should open the file, #read i
ivann1987 [982]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

7 0
9 days ago
Jane's organization recently experienced a security incident that occurred when malware set to trigger on the chief executive of
amid [867]

Answer:

The type of malware involved is a virus

Explanation:

This is because it is malicious software that burrows into another program and typically executes destructive tasks, like erasing data.

4 0
17 days ago
Assume there is a machine with the IP address 129.82.102.63 with netmask /23, and with a parent NW whose netmask is 255.255.224.
8_murik_8 [927]
The complete query is as follows: Assume there exists a machine with the IP address 129.82.102.63 with a netmask of /23, and a parent network (NW) with a netmask of 255.255.224.0. For all answers, refrain from adding spaces, provide full IP addresses/netmasks as requested, and include the "/" in the slash notation.
3 0
21 day ago
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