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Advocard
17 days ago
13

Julia earns $6 an hour babysitting and earns $5 an hour walking dogs. She earned $43 after working a total of 8 hours at her two

jobs.
Complete the system of equations below to represent the situation. Let b = the number of hours that Julia babysits and d = the number of hours she walks dogs.
_ + _ = 8 _ + _ = 43
Solve the system of equations from problem 5 to find the number of hours Julia worked at each job.
Mathematics
2 answers:
Svet_ta [12.7K]17 days ago
8 0
The equations can be set up as follows: b + d = 8 and 6x + 5y = 43. Here, b denotes the hours Julia babysits, and d indicates the hours spent walking dogs. Given that Julia worked a total of 8 hours, this leads to the equation b + d = 8. Considering her earnings of $6 per hour babysitting and $5 walking dogs, accumulating to a total of $43 after 8 hours results in the equation 6x + 5y = 43.
lawyer [12.5K]17 days ago
3 0
5 + 3 equals 8, and adding 8 + 35 gives 43, which is the total I calculated.
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16 days ago
Joey is planning to invest his savings in a fixed income fund. He manages to deposit $700 at the end of the first year, $500 at
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8 0
8 days ago
Kendra is choosing bouquets of flowers for table centerpieces. She decides to buy 40 bouquets for $120 because she thinks that p
babunello [11817]

Answer:

Find below:

Step-by-step explanation:

To determine this, we will either calculate the total cost of acquiring 40 bouquets at $2.50 each or find the single bouquet’s cost at $120.

Cost of one in pack of 40 priced at $120.

120 divided by 40 equals $3

Now, we notice that $3>$2.50

This indicates Kendra has made an error by purchasing the 40 bouquet pack at $120

Hope this helps.

Good Luck

7 0
28 days ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
babunello [11817]

Response:

the expected value of this raffle if you purchase 1 ticket = -0.65

Breakdown of the calculation:

Details:

5,000 tickets are sold at​ $1 each for a charitable raffle

Winners will be chosen at random with cash prizes as follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Therefore, the value and its respective probability can be calculated as follows:

Value                              Probability

$500 - $1 = $499              1/5000

$300 - $1 = $299              3/5000

$50 - $1 = $49                    5/5000

$5 - $1 = $4                     20/5000

-$1                           1 - 29/5000 = 4971/5000

The expected value of the raffle when buying 1 ticket is computed as follows:

E(x) = \sum x * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000} + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016 + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

So, the expected value of this raffle when one ticket is purchased = -0.65

7 0
1 month ago
A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally. A piece of climbing equipment at a
AnnZ [12381]

Response: The following comparison is made.

Detailed explanation:

At the playground, a climbing structure is 6 feet high and stretches 4 feet horizontally.

The slope can be calculated as vertical height divided by horizontal length.

m_1=  6/4 = 3/2 = 1.5

In contrast, a climbing structure in the gym stands 10 feet tall, extending 6 feet horizontally.

Therefore, slope, m_2=  10/6 = 5/3 = 1.67 (approximately)

As such, m_1 < m_2

Thus, the slope of the first climbing structure is less than that of the second.


5 0
1 month ago
Read 2 more answers
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