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nikdorinn
7 days ago
12

A vertical pole, 40 feet tall, casts a shadow onto the ground. If the angle of elevation from the tip of the shadow on the groun

d to the top of the pole is θ=67∘, use the dimensions given to find the length of the shadow, a, in feet. Do not include the units in your answer.

Mathematics
1 answer:
AnnZ [11.9K]7 days ago
3 0
The shadow's length measures 96.6. To find the distance, you can use a right-angle triangle method if you know the angle of elevation. Here, (a) is the adjacent side, (b) is the hypotenuse, and (c) is the opposite side. We know that the adjacent side (a) equals 40, while the opposite side (b) is unknown. The tangent of the angle θ is given by opposite/adjacent; thus, tan 67° = opposite/40. Therefore, the opposite side equals tan 67° multiplied by 40, leading to an adjacent length of 96.6.
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Right triangle XYZ has legs of length XY = 12 and YZ = 6. Point D is chosen at random within the triangle XYZ. What is the proba
Svet_ta [12324]

The "successful" area is half the size of the overall triangle, thus using the concept of similar triangles, the likelihood that the area of triangle XYD does not exceed 12 is 1/4.

8 0
7 days ago
Read 2 more answers
WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the
Inessa [12191]

Answer:

a) P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

The probability can be determined using the complement rule, with the standard normal distribution, an excel sheet, or a calculator.

P(z>1.43)=1-P(z

b) P(X

This probability can also be calculated using the normal standard distribution, an excel sheet, or a calculator.

P(z

c) P(

For this one, the probability can likewise be derived from the standard normal distribution, excel, or a calculator, with specific adjustments:

P(-1.43

Step-by-step explanation:

Previous concepts

Normal distribution refers to a symmetric probability distribution centered around the mean, indicating that occurrences near the mean are more common than those far from it.

The Z-score is a statistic that represents a value's relationship to the average of a set of values, expressed in terms of how many standard deviations it is away from the mean.

Part a

Let X denote the random variable representing the lengths within a population, and for our case, the distribution for X is as follows:

X \sim N(15,3.5)

Where \mu=15 and \sigma=3.5

We seek the probability:

P(X>20)

The most effective way to solve this is by leveraging the normal distribution and the corresponding Z-score:

z=\frac{x-\mu}{\sigma}

By applying this formula, we can find the probability:

P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

Again, this probability can be obtained either using the complement rule, the standard normal distribution, or a calculator.

P(z>1.43)=1-P(z

Part b

P(X

This probability can also be computed using either the normal standard distribution, an excel sheet, or a calculator.

P(z

Part c

P(

In this case, the probability can similarly be acquired with the help of the standard normal distribution, an excel sheet, or a calculator, with particular adjustments:

P(-1.43

5 0
1 month ago
A customer/member owes $10.51 and pays $50.00 in cash. The change due is $39.49. Provide the amount owed using the smallest numb
Leona [12150]

The total number of bills and coins is 14.

Step-by-step explanation:

To minimize the count of bills and coins, start with the largest denominations that fit within the amount.

The change due is $39.49.

Start with:

-$20 bill (largest under $39.49)

Remaining: $19.49

-$10 bill (largest under $19.49)

Remaining: $9.49

-$5 bill (largest under $9.49)

Remaining: $4.49

Then:

4 × $1 bills (to cover $4.49)

Remaining: $0.49

-$0.25 coin (quarter)

Remaining: $0.24

2 × $0.10 coins (dimes)

Remaining: $0.04

4 × $0.01 coins (pennies)

The final composition includes:

1 twenty-dollar bill

1 ten-dollar bill

1 five-dollar bill

4 one-dollar bills

1 quarter

2 dimes

4 pennies

Totaling 14 pieces.

5 0
1 month ago
When the sun is at a certain angle in the sky, a 50-foot building will cast a -foot shadow. What is the length of the shadow in
Svet_ta [12324]

Answer:

0.40 feet

Step-by-step explanation:

For the first scenario, a 50-foot building casts a shadow of 1 foot. Let the angle of elevation of the sun from the shadow be denoted as θ.

Then:

Tan θ = \frac{opposite}{adjacent}

Tan θ = \frac{50}{1}

Tan θ = 50

⇒ θ = Tan^{-1} 50

      = 88.8542

      = 88.85^{o}

The elevation angle is roughly 88.85^{o}.

For a 20-foot pole,

Tan θ = \frac{opposite}{adjacent}

Tan 88.85^{o} = \frac{20}{x}

x = \frac{20}{Tan 88.85^{o} }

 = 0.4015

 = 0.40 feet

The length of the pole's shadow is 0.40 feet.

4 0
11 days ago
Trapezoid STUV with vertices S(-3,6),T(0,7),U(1,4),and V(-5,2): (x,y)>(x+7,y-9)​
AnnZ [11946]

Answer:

Please refer below.

Step-by-step explanation:

Given points:

  • S(-3,6),T(0,7),U(1,4),and V(-5,2)

Translation rule:

  • (x,y) → (x+7,y-9)

New coordinates after applying the rule:

  • S'(4, -3), T'(7, -2), U'(8, -5), V'(2, -7)

For the graph, see attached.

The trapezoid highlighted in blue is STUV while the red trapezoid is S'T'U'V'

7 0
1 month ago
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