a. She utilized 1/10 of the spinach for a salad.b. She allocated 1/2 pound of spinach for the salad.
We can tackle each segment of this issue with a "fraction strip," which visually represents the distribution of spinach used for the party, family, and salad. Refer to the attached image for a comprehensive step-by-step breakdown on how to multiply the fractions to uncover the accurate portions.
The likelihood of observing a sample mean that is less than 18 hours is 0.0082. \nTo evaluate this probability, we calculate the z-score for a sample mean of 18. Accordingly, the probability of getting a sample mean below 18 hours becomes P(z<z(18)). \nThe z-score is calculated as follows: \nz(18) = [(X - M) / s] where: \n- X is the sample mean (18 hours) \n- M is the average hours dentists devote weekly to fillings (20 hours) \n- s is the standard deviation (10 hours) \n- N is the sample size (144) \nSubstituting the numbers leads to: \nz(18) = [(18 - 20) / (10/sqrt(144))]. Using the z-table, we find that P(z<z(18)) is 0.0082.
Answer:
2.5 hours
Step-by-step explanation:
150 divided by 60
150 divided by 60 gives the time
Aubrey's dinner totaled $85. For excellent service, she tips the waitstaff 30%. The tip amount is $25.5. To calculate the tip, we start with the total cost of the dinner, which is $85, and apply the 30% tip rate. So, 30% of $85 is calculated as: Tip = 30% of 85. This results in Aubrey tipping the waitstaff $25.5.
The solution is 20 days, found as follows:
Each of the three friends initially makes 4 bags of dough. After 10 days, each of these bags is split into 4 new bags:
3 friends × 4 bags = 12 bags, and 12 bags × 4 = 48 bags
Then in the following 10 days, 48 bags are again divided into 4 bags each:
48 × 4 = 192 bags
Adding the periods: 10 days + 10 days = 20 days
Therefore, 192 bags are created after 20 days.
