The count of people serves as the independent variable. The picnic's starting cost (initial fee) is $40. When more people attend, the picnic's overall expense rises.
Answer:
Sarah purchased 2 drinks and 6 candies.
Step-by-step explanation:
Let
x ----> the quantity of drinks Sarah bought.
y ----> the number of candies acquired by Sarah.
We know that
the total spent on drinks and candies was $35.50
therefore,
-----> equation A
She bought 3 times more candies compared to drinks.
thus,
-----> equation B
To resolve the equations graphically
The solution lies at the intersection of the two graphs
utilizing a graphing tool
The result is the coordinate (2,6)
therefore,
Sarah bought 2 drinks and 6 candies.
Option B is correct, expressed as 8(25 + x) > 500; solving for x gives x > 37.50
Response:
The answer is many to one
Step-by-step explanation:[[TAG_9]][[TAG_10]][[TAG_11]]
We determine that the true average calorie content as estimated in the sampled population surpasses the actual calorie content. Step-by-step explanation: An article discussed a pilot study where each of the 58 participants was asked to estimate the calorie count of a 12 oz beer known to have 153 calories. The observed sample mean of calorie estimation was 193, with a sample standard deviation of 88. Let

=
true average estimated calorie level within the sampled population. Thus, Null Hypothesis, :
153 calories {indicating that the true average estimated calorie content does not exceed the actual amount}. Alternative Hypothesis,
:
> 153 calories {indicating the true average estimation exceeds the actual}. The appropriate test statistic would be a one-sample t-test statistic, as we lack knowledge of the population standard deviation; Test Statistic = ~t = 
where, sample mean estimated calorie level = 193 calories, s = sample standard deviation = 88, and n = sample size = 58. Therefore, the test statistic = ~t = 3.462. The t-table indicates a critical value of 1.6725 for 57 degrees of freedom at a 0.05 significance level. Since our test statistic of 3.462 > 1.6725, we have sufficient evidence to reject the null hypothesis; thus, affirming that the true average estimated calorie content in the sampled population exceeds the real content.