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Salsk061
14 days ago
9

A sequential circuit has two inputs, w1and w2, and an output, z. Its function is to compare the input sequences on the two input

s. If w1= w2 during any three consecutive clock cycles, the circuit produces z= 1; otherwise, z= 0. The output should be equal to 1 in the same clock cycle when the third occurrence of w1= w2 is detected.

Engineering
1 answer:
Mrrafil [318]14 days ago
5 0

Answer / Explanation

The question provided is lacking in details. It can be searched for online. However, please see the complete question below:

A sequential circuit incorporates two inputs, w1 and w2, and an output z. Its function is to compare the input sequences of both inputs. If w1 equals w2 for any four consecutive clock cycles, the circuit outputs z=1; otherwise, z=0.

For example: w1:0110111000110

w2:1110101000111

z:0000100001110

Please illustrate the state diagram using the minimum number of states.

Answer:

To accurately address this inquiry, we first need to clarify what a sequential circuit is and how input sequences function.

To begin with, a sequential circuit

is identified as a specific type of system used in the digital field, particularly crucial in digital circuit theory. It is structured in such a way that its output depends not only on the present input signal values but also on the sequence of one or more past inputs and outputs that are relevant.

Input sequence:

This references the ordered pattern in which data values are inputted into the circuit.

Revisiting the question, we note that for scoring each state:

+1 for each accurate transition = 2 total per state

+2 for each correct output = 2 total per state

Total for each state = 4

Therefore, the maximum score is 4*5 = 20

Consequently,

If over 5 states are implemented but the logic remains sound: +10 for the entire response

Full credits for any alternative solution utilizing 5 states.

Additionally, it is important to note that input labeled as (w1 = w2), (w1 == w2), (w1 XOR w2), 00, 11, etc., are also acceptable

It is worth mentioning that the presented solution employs more machinery. One can also utilize a Mealy machine, where only 4 states suffice. Even with 5 states, no points will be deducted.

In summary,  X = w1 XOR w2

The required diagram for a clearer understanding of the question is provided below.

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Steam flows at steady state through a converging, insulated nozzle, 25 cm long and with an inlet diameter of 5 cm. At the nozzle
iogann1982 [368]

Answer:

The velocity at exit U_2 is 578.359 m/s

The exit diameter d_e is 1.4924 cm

Explanation:

Provided data includes:

Length of the nozzle L = 25 cm

Inlet diameter d_i = 5 cm

At the nozzle entrance (state 1): Temperature T_1 = 325 °C, Pressure P_1 = 700 kPa, Velocity U_1 = 30 m/s, Enthalpy H_1 = 3112.5 kJ/kg, Volume V_1 = 388.61 cm³/gAt the nozzle exit (state 2): Temperature T_2 = 250 °C, Pressure P_2 = 350 kPa, Velocity U_2, Enthalpy H_2 = 2945.7 kJ/kg, Volume V_2 = 667.75 cm³/g To determine:a. Exit Velocity U_2b. Exit Diameter d_e

a.The Energy Equation can be represented by:ΔH + ΔU² / 2 + gΔz = Q + WAssuming Q = W = Δz = 0Substituting the values yields:

(H_2 - H_1) + (U²_2 - U²_1)  / 2 = 0From which we can derive U_2 = sqrt((2* (H_1 - H_2 )) + U²_1) with the calculations leading to U_2 = sqrt ( 2 * 10^3 * (3112.5 -2945.7) + 900) yielding U_2 = 578.359 m/s

b.

Using mass balance approach, we have U_1 * A_1 / V_1 = U_2 * A_2 / V_2

Here, A = π*d² / 4

This leads to U_1 * d_i² / V_1 = U_2 * d_e² / V_2, thus d_e = d_i * sqrt((U_1 / U_2) * (V_2 / V_1)). Hence, d_e = 5 * sqrt((30 / 578.359) * (667.75 / 388.61)) computes to d_e = 1.4924 cm

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25 days ago
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19 days ago
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Response:

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Explanation:

We have been given;

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-------------

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Response:

The solution to this question is 1273885.3 ∅

Clarification:

The first step is to ascertain the required hydraulic flow rate liquid based on the working pressure if a cylinder with a piston diameter of 100 mm is utilized.

Given that,

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