Answer:
Energy Transfer = 350 kJ
Explanation:
The net work can be derived from the energy balance equation. Thus, we have:
∆KE + ∆PE + ∆U = Q − W
Where
∆KE = ∆PE = 0 (Since there’s no notable change in either kinetic or potential energy of the steam)
Net work comprises the work done by the paddlewheel, Wpw,
and the work on the piston, Wpiston:
W = Wpw + Wpiston
From the data provided, Wpw = −18.5 kJ,
Summarizing results:
Wpw + Wpiston = Q − ∆U
Wpiston = Q − ∆U − Wpw = Q − m (u2 − u1) − Wpw
Where Q = 80 kJ, m = 5 kg, u2 = 2659.6 kJ/kg, and u1 = 2709.9 kJ/kg
= 80 kJ − 5 kg (2659.6 − 2709.9) kJ/kg − (−18.5 kJ)
= 350 kJ
Answer:
Combustion
Explanation:
This relates to an internal-combustion engine.
Answer:
r=0.31
Ф=18.03°
Explanation:
Provided:
Original diameter of bar = 75 mm
Diameter post-cutting = 73 mm
Average diameter of the bar d= (75+73)/2=74 mm
Average length of uncut chip = πd
Average length of uncut chip = π x 74 =232.45 mm
Thus, cutting ratio r
r=0.31
Therefore, the cutting ratio equals 0.31.
Now, the shearing angle is given as
Next by substituting the values
\
Ф=18.03°
Concluding, the shearing angle is 18.03°.
Answer:
a) q = 7671 W
T0 = 47.6°C
b) ΔP = 202.3 N/m²
P = 58.2 W
c) hDarray = 2 times hD of an isolated element.
Explanation:
see the image for the solution.
Answer:
This is the solution code in Python:
- alphabets = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J']
- user_input = input("Enter number of rows and columns: ")
- myArr = user_input.split(" ")
- num_rows = int(myArr[0])
- num_cols = int(myArr[1])
- seats = []
- for i in range(num_rows):
- row = []
- for j in range(num_cols):
- row.append(alphabets[j])
- seats.append(row)
- output = ""
- for i in range(len(seats)):
- for j in range(len(seats[i])):
- output += str(i + 1) + seats[i][j] + " "
- print(output)
Explanation:
Initially, we create a small list of alphabets from A to J (Line 1).
We then request the user to enter the number of rows and columns (Line 3). Given that the input comes as a string (e.g., "2 3"), we utilize the split() method to separate the numbers into individual items in a list (Line 4). The first item (row number) is assigned to variable num_rows, while the second item (column number) goes to num_cols.
Subsequently, we construct the seats list with a nested for-loop (Lines 10-15). Once the seats list is formed, another nested for-loop generates the required output string as per the question (Lines 19-21).
Finally, the output is printed (Line 23). For example, an input of 2 3 results in the output:
1A 1B 1C 2A 2B 2C
