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KATRIN_1
2 months ago
5

The newly elected Chancellor of the Galactic Federation is interested in the opinions of all citizens regarding economic conditi

ons in the galaxy. Unfortunately, she does not have the resources to visit every populated planet or to send delegates to them. Describe how the Chancellor might organize a multi-stage sample to carry out her survey.
Mathematics
1 answer:
lawyer [12.5K]2 months ago
7 0
Step-by-step approach: The Chancellor should implement a multi-stage sampling method for the survey. Initially, random samples of solar systems should be selected from the galaxy, followed by sampling planets within the chosen solar system, and finally, a random selection of countries within those planets.
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Diego’s history teacher writes a test for the class with 26 questions. The test is worth 123 points and has two types of questio
AnnZ [12381]

Answer:

There are 9 essay questions.

Step-by-step explanation:

Let x represent the number of multiple-choice questions and y represent the number of essay questions.

Given that the total question count is 26, we can derive the equation, x+y=26

Additionally, the multiple-choice and essay questions carry values of 3 points and 8 points, respectively.

The overall points available in the test equal 123.

Thus, we set up the following equations:

x+y=26...........................(1)

3x+8y=123............................(2)

If we multiply equation (1) by 3 and subtract equation (2), we obtain:

5y = 45, leading to y = 9

Consequently, from x+y=26, we find x = 26 - y, resulting in x = 17.

Hence, the counts of multiple-choice and essay questions are 17 and 9, respectively.

5 0
3 months ago
Carly has 2 more nickels than dimes in her pocket. She has 40 cents. How many nickels does Carly have How many dimes does Carly
Inessa [12570]
Carly possesses 2 dimes and 4 nickels.
Since a dime is worth 10 cents, with 1 dime and 3 nickels you would have 20 cents; with 2 dimes and 4 nickels, the total would be 40 cents. It is required to have two additional nickels compared to the number of dimes.
8 0
2 months ago
Read 2 more answers
What is true about the solution of StartFraction x squared Over 2 x minus 6 EndFraction = StartFraction 9 Over 6 x minus 18 EndF
PIT_PIT [12445]

Answer:

x=\pm\sqrt{3} and these represent genuine solutions.

Step-by-step explanation:

We have

\frac{x^2}{2x-6}=\frac{9}{6x-18}

Factor both sides' denominators.

\frac{x^2}{2(x-3)}=\frac{9}{6(x-3)}

Simplify.

\frac{x^2}{2}=\frac{9}{6}

x^2=\frac{18}{6}

x=\pm\sqrt{3}

Verify

1) For x=\sqrt{3}

\frac{\sqrt{3}^2}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}

\frac{3}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}

18=18 ---> is valid.

Thus,

x=\sqrt{3} -----> is a legitimate solution.

2) For x=-\sqrt{3}

\frac{-\sqrt{3}^2}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}

\frac{3}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}

18=18 ---> is valid.

Therefore,

x=-\sqrt{3} -----> is a legitimate solution.

Thus,

3 0
3 months ago
Read 2 more answers
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