A machine shop produces heavy duty high endurance 20-inch rods that are meant for use in a variety of military grade equipment.
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod. If such defective rods can be cut so that there is at least 15 consecutive inches without a groove, then the rods can be salvaged for other purposes. If the location of the groove on a rod is described by a uniform distribution, what is the probability that a defective rod can be salvaged?
The likelihood of salvaging a defective rod is 0.50. Given that the machine shop creates heavy-duty 20-inch rods, occasionally, defects occur from grooves or chisel cuts. If these defective rods can be cut such that at least 15 inches remain unblemished, these rods can be salvaged if the groove is located anywhere from 0 to 5 inches on the rod (20 - 15). Thus: P(X ≤ 5) = 0.25 and P(X ≥ 15) = 0.25. The probability of salvaging a defective rod equals P(X ≤ 5) + P(X ≥ 15) = 0.25 + 0.25 = 0.50.
Monster Ski is preferable as Super Ski requires lessons for three days, more than two days, costing over $380 including lessons and travel. On the other hand, Monster Ski's prices are $75 an hour, leading to a total of $300 for 2 hours, and slightly over $305 considering the travel expenses.
Hector will purchase 6 bags of peanuts and 2 bags of popcorn.
Step-by-step explanation:
His plan includes buying 6 peanut bags for a total of $12 and 2 popcorn bags totaling $2. He aimed for 8 bags of snacks overall, with a maximum budget of $14. Hope this is helpful!!!:)
you have to multiply the number by how much it used to be then divide it, but if there is a remainder, then add a zero and combine it all together. I hope you understand and manage to solve it correctly.
