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Shkiper50
3 months ago
8

Consider the system of equations. y = 3x + 2 y = − 2 3 x − 4 Explain why these particular equations can be graphed immediately.

Explain why these particular equations can be graphed immediately.
Mathematics
2 answers:
lawyer [12.5K]3 months ago
7 0

Sample answer, don't copy verbatim!!!: These equations are formatted in slope-intercept style. I can graph the lines by utilizing the y-intercept and slope. By plotting the y-intercept, I can apply the rise over run method to find another point along the line. Then, I can connect the two points with a line.

Inessa [12.5K]3 months ago
5 0
It’s straightforward, as you already have the slope and y-intercepts for each equation, enabling easy graphing.

I hope this is helpful <3
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Radio blackouts are among the most common space weather events to affect Earth. Minor radio blackouts occur, on average, twice p
Zina [12379]

Answer:

a.  P(x = 3) = 0.061313

b. The anticipated number of radio blackouts = 4

c.  It's unclear when the next radio blackout will occur.

d. P(x = 4) = 0.19537

Step-by-step explanation:

Based on the provided details:

A Poisson process is utilized to model the occurrence of this event:

Minor radio blackouts occur, on average, two times annually.

Therefore:

\lambda = 2 \ years

For question (a)

time t = 1/2 (i.e., six months)

Let x represent the likelihood of 3 incidents during the remaining months of the year.

Then:

P(x = 3) = \dfrac{e^{-\lambda t} \times (\lambda t)^x}{x!}

P(x = 3) = \dfrac{e^{-2* 0.5} \times (2 * 0.5)^3}{3!}

P(x = 3) = 0.061313

b).

The expected number of radio blackouts over two years is calculated as follows:

We start with:

t = 2 years

E(x) = λ × t

E(x) = 2 × 2

E(x) = 4

Thus, the predicted number of radio blackouts = 4

c).

The time we must wait until the probability of witnessing the next radio blackout reaches at least 0.5 is as follows:

In this case, time (t) =???

Thus:

P(x =1) = 0.5

P(x = 1) = \dfrac{e^{-\lambda t} \times (\lambda t)^x}{x!} = 0.5

\dfrac{e^{-\lambda t} \times (\lambda t)^x}{x!} = 0.5

Consequently, we are unable to ascertain the probability (50%) of the next radio blackout.

d)

We can compute the probability that the time until the fourth blackout is at most 2 years as follows:

Here;

x =4, t = 2

Thus:

P(x = 4) = \dfrac{e^{-4 } \times (4)^4}{4!}

P(x = 4) = 0.19537

8 0
2 months ago
Which triangle results from a reflection across the line x = 1?
Zina [12379]
The correct answer is option D. Detailed explanation: As per the attached image. Observing the image, the coordinates are outlined. To determine the reflection of a point across a line, the distances from the points to the line must be equal. Point A(1,1) sits on the line x = 1, meaning its reflection A' remains at A'(1,1). Point C(2,5) is a distance of 1 from x = 1 on the right, hence its reflected position C' shifts left by the same distance — subtracting 1 from its x-coordinate places it at C'(1 - 1, 5) or C'(0, 5). Point B(4,1) is positioned 3 from x = 1 on the right; therefore, its reflection B' would also move left by 3 – leading to B'(1 - 3, 1) or B'(-2, 1). Plotting A', B', and C' confirms option D as the correct choice.
7 0
2 months ago
Read 2 more answers
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