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notsponge
4 days ago
10

Automated manufacturing operations are quite precise but still vary, often with distributions that are close to Normal. The widt

h in inches of slots cut by a milling machine follows approximately the
N(0.8750,0.0011)
N(0.8750,0.0011)
distribution. The specifications allow slot widths between 0.8725 and 0.8775 inch.
What proportion (±0.001) of slots meet these specifications?
Mathematics
1 answer:
PIT_PIT [9.1K]4 days ago
8 0
<span>0.977
The mean for our population is 0.8750, and the standard deviation is 0.0011. Let's determine how many standard deviations we need to exceed the specifications.
Low end
 (0.8725 - 0.8750)/ 0.0011 = -0.0025/0.0011 = -2.272727273
High end
 (0.8775 - 0.8750)/ 0.0011 = 0.0025/0.0011 = 2.272727273

We require a range within 2.272727273 deviations from the mean. Referring to a standard normal table, the corresponding value is 0.48848, representing half the percentage. Therefore, 0.48848 * 2 = 0.97696, rounding it to three digits yields 0.977 </span>
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Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6 with a different number appear
babunello [8412]

Answer:

0.2 = 20%

Step-by-step explanation:

The combinations that yield a total of 6 or lower include:

(1,1), (1,2), (1,3), (1,4), (1,5),

(2,1), (2,2), (2,3), (2,4),

(3,1), (3,2), (3,3),

(4,1), (4,2),

(5,1)

(15 combinations in total)

The combinations resulting in a total of 4 are:

(1,3), (2,2), (3,1)

(3 combinations in total)

Thus, the probability of obtaining a sum of 4, given that the total is 6 or less is:

P = 3/15 = 0.2 = 20%

8 0
1 month ago
A train station has installed a system for determining whether bags contain explosives. It has a 95% chance of correctly identif
PIT_PIT [9117]
a) P(identified as explosive) equals P(actual explosive & identified as explosive) + P(not explosive & identified as explosive) = (10/(4*10^6))*0.95+(1-10/(4*10^6))*0.005 = 0.005002363. Thus, the probability that it actually contains explosives given that it's identified as containing explosives is (10/(4*10^6))*0.95/0.005002363 = 0.000475. b) Let the probability of correctly identifying a bag without explosives be a. Therefore, a = 0.99999763, approximately 99.999763%. c) No, even if this becomes 1, the true proportion of explosives will always be below half of the total detected.
3 0
10 days ago
Find three solutions for the linear equation 4x −3y = 1, and plot the solutions as points on a coordinate plane.
lawyer [9240]

Answer:

(1, 1), (2, 2.333) and (3, 3.666).

Step-by-step explanation:

To solve this equation, we can select various values for x and then compute the corresponding y values.

<pFor instance, when x = 1, we find:

4*1 - 3y = 1

3y = 3

y = 1

When x = 2, we discover:

4*2 - 3y = 1

3y = 7

y = 2.333

Then for x = 3, we have:

4*3 - 3y = 1

3y = 11

y = 3.666

Therefore, the coordinates we will plot are (1, 1), (2, 2.333), and (3, 3.666).

Refer to the attached image for the plot.

4 0
25 days ago
According to the U.S. Census Bureau (2016), a substantial pay gap still exists. The average American man, with an advanced colle
Leona [9271]

Answer:

The earnings gap, over a career spanning 30 years, between men and women totals $1,200,150

Step-by-step explanation:

Calculated annually.

The typical male earns $90,761 each year.

The typical female earns $50,756 per annum.

Therefore, the annual difference is:

90,761 - 50,756 = 40,005

Across 30 years:

30*40,005 = 1,200,150

The earnings gap over a 30-year career, when comparing men and women, is $1,200,150

0 0
1 month ago
Express x in term of y:x/7+2y=6​
AnnZ [9099]

Answer:

You need to multiply the denorminator both sides in order to form x note the subject:

\frac{x}{7 + 2y} = 6

x = 6(7 + 2y)

8 0
1 month ago
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