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Serga
27 days ago
9

Mechanics paper/Math (please helpp!!!)

Mathematics
1 answer:
Inessa [12.5K]27 days ago
4 0

Response:

  (i) 15 m, 6 m/s

  (ii) 90 m

Detailed explanation:

(i) For a certain acceleration (a) starting from rest, the distance traveled (d) at time t is expressed as...

  d = (1/2)at^2

The distance Ben covers in the 5 seconds of acceleration is...

  d = (1/2)(1.2 m/s²)(5 s)² = 15 m

Additionally, Ben’s velocity at this instant is...

  s = (1.2 m/s²)(5 s) = 6 m/s

__

(ii) After 5 seconds of walking by Ben, Alan has walked for 10 seconds, accumulating distance (10 s)(4 m/s) = 40 m. The distance difference between them of 40 - 15 = 25 m is being closed at the rate of their speed difference: (6 m/s) -(4 m/s) = 2 m/s.

It will take an additional (25 m)/(2 m/s) = 12.5 s for Ben to catch up to Alan. In the total of 22.5 s during which Alan has been moving before they reunite, he will have traveled...

  (22.5 s)(4 m/s) = 90 m... which is the distance OP

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Complete Question

Identify all decimals equivalent to ( 9 × 100 ) + ( 2 × 10 ) + ( 3 × 1/10 ) + ( 5 × 1/100 ). A. 92.35 B. 920.350 C. 902.35 D. 92.350 E. 920.35 F. 920.035

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E. 920.35

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( 9 × 100 ) + ( 2 × 10 ) + ( 3 × 1/10 ) + ( 5 × 1/100)

Step 1

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Step 2

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Step 3

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