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Licemer1
2 months ago
15

Select all decimals that are equivalent to ( 9 × 100 ) + ( 2 × 10 ) + ( 3 × 1 10 ) + ( 5 × 1 100 ) . A. 92.35 B. 920.350 C. 902.

35 D. 92.350 E. 920.35 F. 920.035
Mathematics
1 answer:
AnnZ [12.3K]2 months ago
4 0

The question is not properly framed

Complete Question

Identify all decimals equivalent to ( 9 × 100 ) + ( 2 × 10 ) + ( 3 × 1/10 ) + ( 5 × 1/100 ). A. 92.35 B. 920.350 C. 902.35 D. 92.350 E. 920.35 F. 920.035

Response:

E. 920.35

Explanation:

( 9 × 100 ) + ( 2 × 10 ) + ( 3 × 1/10 ) + ( 5 × 1/100)

Step 1

(900) + (20) + (3/10) + (5/100)

Step 2

900 + 20 + 0.3 + 0.05

Step 3

920.35

Thus, the result is 920.35

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What is the relative frequency of the revenue earned by B&B Motors from sales of mini trucks compared to the total sales rev
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Answer: 0.46

Step-by-step explanation:

B&B Motors' mini trucks yield 0.59; all four companies combined yield 0.39; mini trucks yield 0.13. Hence, 0.59 - 0.13 equals 0.46.

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2 months ago
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WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the
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Answer:

a) P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

The probability can be determined using the complement rule, with the standard normal distribution, an excel sheet, or a calculator.

P(z>1.43)=1-P(z

b) P(X

This probability can also be calculated using the normal standard distribution, an excel sheet, or a calculator.

P(z

c) P(

For this one, the probability can likewise be derived from the standard normal distribution, excel, or a calculator, with specific adjustments:

P(-1.43

Step-by-step explanation:

Previous concepts

Normal distribution refers to a symmetric probability distribution centered around the mean, indicating that occurrences near the mean are more common than those far from it.

The Z-score is a statistic that represents a value's relationship to the average of a set of values, expressed in terms of how many standard deviations it is away from the mean.

Part a

Let X denote the random variable representing the lengths within a population, and for our case, the distribution for X is as follows:

X \sim N(15,3.5)

Where \mu=15 and \sigma=3.5

We seek the probability:

P(X>20)

The most effective way to solve this is by leveraging the normal distribution and the corresponding Z-score:

z=\frac{x-\mu}{\sigma}

By applying this formula, we can find the probability:

P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

Again, this probability can be obtained either using the complement rule, the standard normal distribution, or a calculator.

P(z>1.43)=1-P(z

Part b

P(X

This probability can also be computed using either the normal standard distribution, an excel sheet, or a calculator.

P(z

Part c

P(

In this case, the probability can similarly be acquired with the help of the standard normal distribution, an excel sheet, or a calculator, with particular adjustments:

P(-1.43

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2 months ago
A job calls for installing 270 lighting fixtures. If 81 fixtures have been installed so far, what
tester [12383]
70%Step-by-step explanation:First, determine how many fixtures are left to install.270-81=189. The fraction representing the work still to be done is the count of fixtures to install divided by the total amount. So, % of work remaining equals 189 divided by 270, which equals 0.7. Converting this to percentage form gives us 0.7 * 100% = 70%.
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1 month ago
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