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Sedbober
13 days ago
10

Dust,dirt, or metal chips can pose a potential what kind of injury risk in a shop

Engineering
1 answer:
Viktor [391]13 days ago
5 0

Answer:

In a workshop, there is a risk of eye injury from dust, dirt, or metal shavings.

Explanation:

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An air duct heater consists of an aligned array of electrical heating elements in which the longitudinal and transverse pitches
Kisachek [356]

Answer:

a) q = 7671 W

T0 = 47.6°C

b) ΔP = 202.3 N/m²

P = 58.2 W

c) hDarray = 2 times hD of an isolated element.

Explanation:

see the image for the solution.

4 0
1 month ago
Given num_rows and num_cols, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print
Viktor [391]

Answer:

This is the solution code in Python:

  1. alphabets = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J']
  2. user_input = input("Enter number of rows and columns: ")
  3. myArr = user_input.split(" ")
  4. num_rows = int(myArr[0])
  5. num_cols = int(myArr[1])
  6. seats = []
  7. for i in range(num_rows):
  8. row = []
  9. for j in range(num_cols):
  10. row.append(alphabets[j])
  11. seats.append(row)
  12. output = ""
  13. for i in range(len(seats)):
  14. for j in range(len(seats[i])):
  15. output += str(i + 1) + seats[i][j] + " "
  16. print(output)

Explanation:

Initially, we create a small list of alphabets from A to J (Line 1).

We then request the user to enter the number of rows and columns (Line 3). Given that the input comes as a string (e.g., "2 3"), we utilize the split() method to separate the numbers into individual items in a list (Line 4). The first item (row number) is assigned to variable num_rows, while the second item (column number) goes to num_cols.

Subsequently, we construct the seats list with a nested for-loop (Lines 10-15). Once the seats list is formed, another nested for-loop generates the required output string as per the question (Lines 19-21).

Finally, the output is printed (Line 23). For example, an input of 2 3 results in the output:

1A 1B 1C 2A 2B 2C

8 0
1 month ago
A distância entre duas retas reversas é a medida de um segmento orientado que *?
alex41 [359]
Fatec – SP) Let A be a point on line r, which is contained within plane α. It holds true that: a) there is exactly one line that is perpendicular to line r at point A. b) there exists one unique line, not lying in plane α, that is parallel to line r. c) there are infinitely many distinct planes that are parallel to plane α and contain line r. d) there are infinitely many distinct planes that are perpendicular to plane α and contain line r. e) there are countless distinct lines contained within plane α that are parallel to line r.
8 0
7 days ago
A thin-film gold conductor for an integrated circuit in a satellite application is deposited from a vapor, and the deposited gol
mote1985 [299]

Answer:

Explanation:

The equilibrium vacancy concentration can be described by:

nv/N = exp(-ΔHv/KT),

where T is the temperature at which vacancies form,

K = Boltzmann's constant,

and ΔHv = enthalpy of vacancy formation.

Rearranging this equation to express temperature allows you to calculate it using the provided values. A detailed breakdown of the process is included in the attached file.

5 0
1 month ago
The rate of flow of water in a pump installation is 60.6 kg/s. The intake static gage is 1.22 m below the pump centreline and re
mote1985 [299]

Answer:

The power of the pump is 23.09 kW.

Explanation:

Parameters

gravitational constant, g = 9.81 m/s^2

mass flow rate, \dot{m} = 60.6 kg/s

flow density, \rho = 1000 kg/m^3

efficiency of the pump, \eta = 0.74

output gauge pressure, p_o = 344.75 kPa

input gauge pressure, p_i = 68.95 kPa

cross-sectional area of output pipe, A_o = 0.069 m^2

cross-sectional area of input pipe, A_i = 0.093 m^2

height of discharge, z_o = 1.22 m - 0.61 m = 0.61 m (evaluated at pump’s maximum height of 1.22 m)

input height, z_i = 0 m

hydraulic power of the pump,P =? kW

Initially, the volumetric flow (Q) needs to be determined

Q = \frac{\dot{m}}{\rho}

Q = \frac{60.6 kg/s}{1000 kg/m^3}

Q = 0.0606 m^3/s

Next, compute the velocity (v) for both input and output

v_o = \frac{Q}{A_o}

v_o = \frac{0.0606 m^3/s}{0.069 m^2}

v_o = 0.88 m/s

v_i = \frac{Q}{A_i}

v_i = \frac{0.0606 m^3/s}{0.093 m^2}

v_i = 0.65 m/s

Subsequently, the total head (H) can be calculated

H = (z_o - z_i) + \frac{v_o^2 - v_i^2}{2 \, g} + \frac{p_o - p_i}{\rho \, g}

H = (0.61 m - 0 m) + \frac{{0.88 m/s}^2 - {0.65 m/s}^2}{2 \, 9.81 m/s^2} + \frac{(344.75 Pa-68.95 Pa)\times 10^3}{1000 kg/m^3 \, 9.81 m/s^2}

H = 28.74m

Finally, the computation of pump power is done as follows

P = \frac{Q \, \rho \, g \, H}{\eta}

P = \frac{0.0606 m^3/s \, 1000 kg/m^3 \, 9.81 m/s^2 \, 28.74m}{0.74}

P = 23.09 kW

6 0
1 month ago
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