A 90-hp (shaft output) electric car is powered by an electric motor mounted in the engine compartment. If the motor has an avera

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are special functions for use with the insertion (<<) and extraction (>>) operators on C++ stream objects, while the 'cout' statement outputs content to the standard output device in C++ programming.

setw: specifies the minimum width of the output field

setprecision: defines the number of decimal places for floating-point value formatting.

fixed: sets the format flag for floating-point streams.

left: left-aligns the output.

A) This statement shows the number 34.789 in a field that provides eight character spaces with two decimal precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) Here, the number 7.0 is displayed within six spaces with three decimal precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) This command prints 5.789e+12 in fixed-point format.  cout<<fixed<<5.789E12;

D) This statement left-aligns the number 67 across a field of six spaces. cout<<left<<setw(7)<<67;

Answer:

a) , b)

Explanation:

a) The uniform dresser can be modeled using specific equilibrium equations:

Following some algebraic manipulations, the formulated equation is derived:

b) Similarly, the man can be represented by a set of equilibrium equations:

After some algebraic changes, the expression for the coefficient of static friction comes out as:

Answer:

1.312 in

Explanation:

The details provided in the question are:

The weight of the compressor, W is 227 pounds.

It has 4 legs.

The maximum permissible pressure is 42 psi.

Let F represent the force exerted by each leg.

Thus,

W = 4F,

or

227 pounds = 4F,

implying that:

F = 56.75 pounds.

Furthermore,

Force = Pressure × Area,

therefore:

56.75 pounds = 42 psi × πr²  [ r signifies the radius of one leg]

Consequently, we find:

r² = 0.4301,

and thus:

r = 0.656;

resulting in a diameter equal to 2r = 2 × 0.656,

which equals 1.312 in.

In the scenario of a metal ingot cooling slowly, the microstructure tends to be coarse. The surface, exposed to higher temperatures for extended periods during cooling, features smaller grain sizes as they have less time to form. However, as we delve deeper into the ingot, the grains gradually extend, leading to equiaxed grain formation at the center.

Response:

a) 144.000 seconds

b) and c) Battery voltage and power graphs are in the attached image.

     where D:{0<t h="" />

d) 1620 J

Description:

a) The initial response is derived via a rule of three

b) Using the line equation from the starting point (0 seconds, 1.5 V)

where m denotes the slope.

where V represents voltage in volts and t signifies time in seconds

along with P and m.

d) By evaluating that count.