A 90-hp (shaft output) electric car is powered by an electric motor mounted in the engine compartment. If the motor has an avera
1 answer:
Answer:
Heat supply rate is measured at 8.901 horsepower.
Explanation:
Energy efficiency of the electric vehicle, as per Thermodynamics (), is the proportion of translational mechanical power (
), expressed in horsepower, and electrical energy (
), also in horsepower. The heat supply rate (
), indicated in horsepower, that the motor delivers to the engine bay under full load can be determined by subtracting the translational mechanical energy from the electric energy. This is expressed as:
(1)
(2)
(3)
If we have the values of and
, the heat supply rate can be calculated as:
The heat supply rate amounts to 8.901 horsepower.
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Answer:
a) The phase before eutectoid is commonly referred to as cementite, with the chemical formula Fe₃C.
b) The total mass of ferrite obtained is 0.8311 kg.
The total cementite mass equals 0.1689 kg.
c) The total cementite mass accounts for 0.9343 kg.
Explanation:
Provided:
1 kg of austenite
a carbon content of 1.15 wt%
Cooled below 727°C
Questions:
a) Identify the proeutectoid phase.
b) Calculate the mass of total ferrite and cementite, Wf =?, Wc =?
c) Determine the mass of both pearlite and the proeutectoid phase, Wp =?
d) Create a schematic to illustrate the resulting microstructure.
a) The proeutectoid phase is referred to as cementite with the formula Fe₃C.
b) To find the total mass of formed ferrite:
With:
Ccementite = composition of cementite = 6.7 wt%
C₁ = composition of phase 1 = 0.022 wt%
C₂ = overall composition = 1.15 wt%
Inserting the values yields:
For the total mass of cementite:
c) The mass of pearlite:
d) The diagram illustrates the different compositions: (pearlite, proeutectoid cementite, ferrite, eutectoid cementite)
Answer:
a) q = 7671 W
T0 = 47.6°C
b) ΔP = 202.3 N/m²
P = 58.2 W
c) hDarray = 2 times hD of an isolated element.
Explanation:
see the image for the solution.
