Let Q(x) be the statement "x +1 2x." If the domain consists of all integers, what are these truth values?

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) To find P(X=2), we calculate: P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4) which equals 1 - 0.41 - 0.18 - 0.06 - 0.06, resulting in 0.29

b) For P(X<2), we sum P(X=0) and P(X=1): 0.41 + 0.18 yields 0.59

c) To obtain P(X≤2), we add P(X=0), P(X=1), and P(X=2): 0.41 + 0.18 + 0.29 equals 0.88

d) To calculate P(X>2), we find P(X=3) + P(X=4): 0.06 + 0.06 gives us 0.12

e) For P(X=1 or X=4), we use the union of probabilities: P(X=1) + P(X=4) which is 0.18 + 0.06, resulting in 0.24

f) P(1≤X≤4) is found by adding P(X=1), P(X=2), P(X=3), and P(X=4): 0.18 + 0.29 + 0.06 + 0.06 results in 0.59

The illustration is omitted. Please see the attachment below.

Answer:

The area of the shaded sector is 144π square units.

Step-by-step breakdown:

Given:

The central angle for the sector is,

The circle's radius is,

The area of a sector with radius 'R' and angle can be determined with:

Substituting gives

Thus, the area of the shaded sector calculates to 144π square units.

In the absence of a specific question posed, below are the potential inquiries along with their respective answers:

P(fewer than 4 tosses)
= P(one toss) + P(two tosses) + P(three tosses)
= (3/4) + (3/4)(1/4) + (3/4)(1/4)^2
= 0.984375


Expected value
= 1 / p
= 1 / (3/4)
= 4 / 3

Variance
= (1 - p) / p^2
= (1 - (3/4)) / (3/4)^2
= (1/4) / (9/16)
= 4 / 9

Standard deviation
= sqrt(Variance)
= sqrt(4 / 9)
= 2 / 3

Answer:

Aproximadamente 428 N

Step-by-step explanation:

Peso = 1,500 * 9.8 = 14,700 N

Densidad = Masa ÷ Volumen

1,030 = 1,500 ÷ V

V = 1,500 ÷ 1,030 = 1.46 m^3.

La fuerza de flotación = Densidad * g * V

La fuerza de flotación = 1,000 * 9.8 * (1,500 ÷ 1,030)

La fuerza de flotación = 9,800 * (1,500 ÷ 1,030) = 14,272 N.

La fuerza neta = 14,700 – [(9,800 * (1,500 ÷ 1,030)]