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kumpel
2 months ago
6

Let Q(x) be the statement "x +1 2x." If the domain consists of all integers, what are these truth values?

Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
7 0

Response:

a) True

b) True

c) False

d) True

e) False

f) True

g) False

Explanation:

a) Q(0) holds true because;

when substituting x= 0 in x+1>2x

==> 0+1>2×0

==> 1>0

b) Q(-1) is accurate because;

if we input x= -1 into x+1>2x

==> -1+1>2 (-1)

==> 0> -2

c) Q(1) is incorrect because;

by inserting x=1 into x+1>2x

==> 1+1> 2 ×1

==> 2>2

which is untrue!

d) The assertion is accurate because;

When x=0 is inputted in x+1>2x

==> 0+1>2×0

==> 1>0

e) The statement is untrue because;

input x=1 yields a false outcome for the statement !

f) The assertion is valid because;

Supposing x=3,

3+1≤2×3

==> 4≤6

This makes the statement accurate

g)  The assertion is incorrect because

Assuming x=0 leads to x+1≤2x, resulting in,

0+1≤2×0

==> 1≤0

This is false - thus x+1≥2x is valid

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Answer:

Elia took \dfrac{5}{11} hour to cycle from her residence to the beach, \dfrac{6}{11} hour to return, and traveled

8\dfrac{2}{11} kilometers from her home to the beach and

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Step-by-step explanation:

1. Let b represent the hours Elia spent cycling to the beach, and p the time taken for the return trip to the park. The combined time for both rides equals 1 hour, represented as

b + p = 1

2. With a constant speed of 18 km/h on her way to the beach, in b hours, she covered 18b kilometers. She then rode back from the beach to the park at a steady speed of 15 km/h, which amounted to 15p kilometers.

Since the distances for both trips are identical, we establish

18b = 15p

3. Solve the two equations:

\left\{\begin{array}{l}b+p=1\\ \\18b=15p\end{array}\right.

Using the first equation

b=1-p

Insert this solution into the second equation

18(1-p)=15p\\ \\18-18p=15p\\ \\18=18p+15p\\ \\33p=18\\ \\p=\dfrac{18}{33}=\dfrac{6}{11}\\ \\b=1-\dfrac{6}{11}=\dfrac{5}{11}

Elia took \dfrac{5}{11} hour to cycle to the beach, \dfrac{6}{11} hour on her return, and covered

18\cdot \dfrac{5}{11}=\dfrac{90}{11}=8\dfrac{2}{11} kilometers going to the beach and

15\cdot \dfrac{6}{11}=\dfrac{90}{11}=8\dfrac{2}{11} kilometers returning to her home.

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