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Gnoma
2 months ago
6

It say a machinist can produce 114 parts in 6min at at this rate how many parts can the machinist produce in 15 min

Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
8 0
114/6=9 parts per minute. 9 parts * 15 minutes= 135 parts
You might be interested in
Suma numerelor de forma a4b cu produsul cifrelor 24 este egala cu
AnnZ [12381]

Answer:

The correct response is: b)

Step-by-step explanation:

a4b=24, where a × 4 × b = 24 implies a × b = 6

The pairs of numbers with a product of 6 include: {1,6} and {2,3}

In base 10, a4b translates to 100a + 40 + b

Calculating gives us:

100×1+40+6=146

100×6+40+1=641

100×2+40+3=243

100×3+40+2=342

Summing these results yields: 146 + 641 + 243 + 342 = 1372

The correct answer is: b)

6 0
3 months ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
Inessa [12570]

Answer: D) \$50\pm\$11.08

Step-by-step explanation:

Based on the provided information, we have

Sample size: n= 15

sample mean: \overline{x}=\$50.50

Sample standard deviation: s= $20

Since the population standard deviation is not known, we utilize a t-test.

For a significance level of 95% confidence: \alpha=1-0.95=0.05

Critical t-value : t_{n-1, \alpha/2}=t_{014,0.025}=2.145  [Using the Student's t-value table]

The required 95% confidence interval yields:-

\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08

Thus, the sought-after 95% confidence interval for the mean amount spent by credit card customers during their initial visit to the new store in the mall, assuming normal distribution of the spending amounts, is:

\$50\pm\$11.08

5 0
2 months ago
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