Answer:
The variable x lies within the interval of all positive real numbers less than 5 cm.
Detailed solution:
Problem statement:
Determine the volume of the open-topped box as a function of the side length x (in centimeters) of the square cutouts.
Refer to the provided diagram for clarity.
Define:
x → length in centimeters of each square cutout side
The volume of the box with open top can be written as:
Given this, we have:
By substitution:
Determine the domain of x:
Because:
Therefore:
Domain is the interval (0,5)
That means all real numbers strictly greater than zero and less than 5 cm are valid for x.
Hence, the volume V as a function of x is:
The graph indicates that x never goes below 0. This means the point (-1,0) is not included in the graph. Therefore, D is the only valid option.
Answer:
m = - 3
Step-by-step explanation:
a³ + 27 can be recognized as a sum of cubes, which factors generally as
a³ + b³ = (a + b)(a² - ab + b²). Therefore:
a³ + 27
= a³ + 3³
= (a + 3)(a² - 3a + 9).
By comparing a² - 3a + 9 to a² + ma + 9, we find that
m = - 3.
The domain refers to all potential input values, specifically represented by the x-axis on a graph. Conversely, the range includes all possible output values, depicted along the y-axis.
The graph clearly extends horizontally from (-∞,∞) on the x-axis, indicating that its domain is (-∞,∞).
Similarly, it can be seen that the graph stretches vertically from (-∞,∞) on the y-axis, denoting that the range is also (-∞,∞).
This indicates the function includes an infinite array of values. Therefore, there are no limitations on either the domain or the range for this function.
Since m∠abe = 2b, and angle abe consists of angles abf and ebf, we can write:
m∠abe = m∠abf + m∠ebf
To find m∠ebf, rearrange:
m∠ebf = m∠abe - m∠abf
Substitute the given expressions:
m∠ebf = 2b - (7b - 24)
Simplify:
m∠ebf = 2b - 7b + 24
m∠ebf = -5b + 24.
