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Sedbober
1 month ago
5

What is the quotient (2x4 – 3x3 – 3x2 + 7x – 3) ÷ (x2 – 2x + 1)?

Mathematics
2 answers:
Inessa [12.5K]1 month ago
8 0

Answer:

Quotient: 2x^2+x-3

Refer to the attached document.

Step-by-step explanation:

Provided: (2x^4-3x^3-3x^2+7x-3)\div (x^2-2x+1)

A rational expression is provided, and we need to compute the quotient.

We will utilize long division to obtain the quotient.

Initially, we eliminate 2x^4 by x^2

x^2-2x+1 ) 2x^4-3x^3-3x^2+7x-3 ( 2x^2+x-3

-2x^4+4x^3-2x^2

x^3-5x^2+7x

-x^3+2x^2-x

-3x^2+6x-3

3x^2-6x+3

0

Thus, the result of the division is 2x^2+x-3

babunello [11.8K]1 month ago
5 0

Here are two polynomials:

1. The dividend - f(x)=2x^4 - 3x^3 - 3x^2 + 7x - 3

2. The divisor - g(x)=x^2 - 2x + 1.

As the divisor is a perfect square g(x)=x^2 - 2x + 1=(x-1)^2, it is necessary to determine the result of dividing f(x) by (x-1):

f(x)=2x^4 - 3x^3 - 3x^2 + 7x - 3=(x-1)(2x^3-x^2-4x+3)=(x-1)(x-1)(2x^2+x-3)=(x-1)^2(2x^2+x-3)=g(x)(2x^2+x-3).

Thus, the quotient obtained is 2x^2+x-3.

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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
Svet_ta [12734]

We are given the triangle

△ABC, with m∠A=60° and m∠C=45°, and AB=8.

To start, we will calculate all angles and sides.

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m∠A + m∠B + m∠C = 180.

Substituting the known values,

60° + m∠B + 45° = 180.

This gives us m∠B = 75°.

Calculating BC:

Using the law of sines,

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We can substitute in the values.

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Now we'll input the values.

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We substitute values here as well.

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3 months ago
Read 2 more answers
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zzz [12365]

Answer:

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

Step-by-step explanation:

In order to simplify the expression \frac{3x^{-6}y^{-3} }{15x^{2}y^{10} } where x ≠ 0, y ≠ 0, we must work through the given expression.

\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }\\= \frac{3}{15} x^{-6-2}y^{-3-10}\\ = \frac{3}{15}x^{-8}y^{-13} \\ =\frac{1}{5}x^{-8}y^{-13} \\

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

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