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tresset_1
2 months ago
15

The human eye can respond to as little as 10^−18 J of light energy. For a wavelength at the peak of visual sensitivity, 550 nm,

how many photons lead to an observable flash?
Physics
2 answers:
Yuliya22 [3.3K]2 months ago
7 0
The fundamental equation is derived from Mr. Planck: E=h \nu, where h is Planck’s constant and ν is the frequency. This relationship describes the energy per photon at a specific frequency. Although a wavelength is provided, it can easily be converted to frequency using the equation: c= lambda / nu, where c denotes the speed of light; λ (lambda) is the wavelength; and ν is the frequency. Once the energy of a photon with a wavelength of 550nm is determined, it will show how many photons are needed to gather 10^-18J. Remember to pay attention to the units.
ValentinkaMS [3.4K]2 months ago
6 0
The result is: 3 photons. To explain: The energy of a photon (E) can be formulated using: E = h*c/λ. Here, h represents Planck's constant (6.63x10⁻³⁴ J.s), λ signifies the wavelength (550 nm = 5.50x10⁻⁷m), and c stands for the speed of light (3.00x10⁸ m/s). Thus, E= (6.63x10⁻³⁴ * 3.00x10⁸)/(5.50x10⁻⁷) results in E = 3.62x10⁻¹⁹ J, which is the energy for one photon. Since the human eye can respond to 10⁻¹⁸ J, it follows that: 1 photon corresponds to 3.62x10⁻¹⁹ J, leading to a simple calculation resulting in approximately 2.76, which rounds to 3 photons.
You might be interested in
Multiply the number 4.48E-8 by 5.2E-4 using Google. What is the correct answer in scientific notation?
Ostrovityanka [3204]

Answer:

2.32\times 10^{-11}

Explanation:

The first number is 4.48\times 10^{-8}.

The second number is 5.2\times 10^{-4}.

We must multiply these two numbers together.

4.48\times 10^{-8}\times 5.2\times 10^{-4}=(4.48\times 5.2)\times 10^{(-8-4)}\\\\=23.296\times 10^{-12}

In scientific notation: 2.32\times 10^{-11}

Therefore, this is the solution you are looking for.

8 0
4 months ago
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